在我的 JSP 页面中,我使用以下脚本:
<script type="text/javascript">
$("#birthDate").datepicker({ dateFormat: 'dd/mm/yy' });
$("#update").click(function (e) {
var res = true;
var alertMsg = "";
$(".required").each(function (index) {
if (this.value == null || this.value.length == 0) {
alertMsg += this.name + " can't be empty! \n";
res = false;
}
});
if (res) {
var response = $("#updateForm").submit();
Window.location.reload();
} else {
alert(alertMsg);
}
})
但是,请求的资源不可用,并且我收到此异常:
HTTP Status 500 -
type Exception report
message
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
java.lang.RuntimeException: org.springframework.remoting.RemoteAccessException: Could not access remote service at [http://some.resource.com]; nested exception is javax.xml.ws.WebServiceException: java.lang.IllegalStateException: Current event not START_ELEMENT or END_ELEMENT
com.dn.eb.controller.UpdateAccountServlet.throwException(UpdateAccountServlet.java:140)
com.dn.eb.controller.UpdateAccountServlet.doPost(UpdateAccountServlet.java:122)
javax.servlet.http.HttpServlet.service(HttpServlet.java:641)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
root cause
org.springframework.remoting.RemoteAccessException: Could not access remote service at [http://some.resource.com]; nested exception is javax.xml.ws.WebServiceException: java.lang.IllegalStateException: Current event not START_ELEMENT or END_ELEMENT
org.springframework.remoting.jaxws.JaxWsPortClientInterceptor.doInvoke(JaxWsPortClientInterceptor.java:510)
org.springframework.remoting.jaxws.JaxWsPortClientInterceptor.invoke(JaxWsPortClientInterceptor.java:487)
org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:172)
org.springframework.aop.framework.JdkDynamicAopProxy.invoke(JdkDynamicAopProxy.java:202)
$Proxy98.updateAccountRecord(Unknown Source)
com.dn.eb.controller.UpdateAccountServlet.doPost(UpdateAccountServlet.java:117)
javax.servlet.http.HttpServlet.service(HttpServlet.java:641)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
如何处理这个异常,以便在我的页面上显示错误消息?
最佳答案
您需要在 web.xml 中声明错误页面:
<error-page>
<exception-type>java.lang.Throwable</exception-type>
<location>/error.jsp</location>
</error-page>
现在应用程序抛出的任何Throwable
都将调用error.jsp。或者这样:
<error-page>
<error-code>500</error-code>
<location>/error.jsp</location>
</error-page>
所有 500 个错误都会调用 error.jsp。
error.jsp是一个错误页面,可用于显示错误消息,在error.jsp中声明页面指令:
<%@ page isErrorPage="true"%>
这为您的 JSP 提供了隐式异常
对象的句柄。
关于java - 处理 HTTP 状态 500,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17403033/