java - GSON 只解析对象名称

Question

我正在尝试使用 GSON 解析 JSON，我想我已经掌握了它的窍门。我遇到的问题是它似乎在对象名称之后停止解析。

    public static void main(String[] args) throws Exception {
    Gson gson=new Gson();
    String json = "{\"k1\":\"v1\",\"k2\":\"v2\"}";
    Map<String,String> map=new HashMap<String,String>();
    map=(Map<String,String>) gson.fromJson(json, map.getClass());
    System.out.println(map.keySet());
}

工作正常并输出:

[k1，k2]

我可以使用这些键来获取正确的值，这就是我想要做的。

如果我对来自 json.org 的 JSON 对象使用相同的代码

{
    "glossary": {
        "title": "example glossary",
        "GlossDiv": {
            "title": "S",
            "GlossList": {
                "GlossEntry": {
                    "ID": "SGML",
                    "SortAs": "SGML",
                    "GlossTerm": "Standard Generalized Markup Language",
                    "Acronym": "SGML",
                    "Abbrev": "ISO 8879:1986",
                    "GlossDef": {
                        "para": "A meta-markup language, used to create markup languages such as DocBook.",
                        "GlossSeeAlso": ["GML", "XML"]
                    },
                    "GlossSee": "markup"
                }
            }
        }
    }
}

我得到的唯一输出是

[词汇表]

我觉得我明显遗漏了一些东西，有人可以帮我指出正确的方向吗？

谢谢。

Answer 1

JSON 对象(包含 "glossary" )比 Map 更复杂。可转换为 Java 的 JSON 对象示例 Map<String, String>将是:

{"key1": "value1", "key2": "value2", "key3": "value3"}

However, in the example JSON object, there is a string key whose value is JSON object, not a String, which does not convert to Map<String, String>:

{"key": {"anotherKey": "some value"}}

There is an example from the Gson homepage here. To properly de-serialize your example, you will have to use a combination of JsonParser and Gson. For example,

String jsonObject = "your example";
JsonParser parser = new JsonParser();
JsonObject obj = parser.parse(jsonObject).getAsJsonObject();
JsonObject glossary = obj.get("glossary");

等等...