java - 从按钮获取输入并验证其正确还是错误

Question

我正在创建一台具有 pin 功能的 ATM 机。问题是我想在用户按下按钮时从按钮获取输入并验证其正确还是错误。当按下按钮时，它将把结果存储在字符串中。然后它将用于验证其正确还是错误。例如:用户A按下012345。然后每个数字将被存储到另一个字符串中以进行验证。然后将该字符串与引脚进行比较。

公共(public)类atmMachine:

int numberPinButton = 10;
String pin = "012345";
String zero, one, two, three, four, five, six, seven, eight, nine;

公共(public) atm 机:

panel = new JPanel();
pinButton = new JButton[numberPinButton];
for(int i = 0; i < numberPinButton; i++) {
    pinButton[i] = new JButton("" + i);
    pinButton[i].addActionListener(this);
    panel.add(pinButton[i]);
}
enterButton = new JButton("Enter");
enterButton.addActionListener(this);
panel.add(enterBtn);
panel.setBorder(BorderFactory.createTitledBorder("Enter your pin:"));
add(panel, BorderLayout.WEST);

已执行的公共(public)无效操作:

public void actionPerformed(ActionEvent event) {
        if(event.getSource() == pinButton[0]) {
            zero = "0";
        } else if(e.getSource() == pinButton[1]) {
            one = "1";
        } else if(e.getSource() == pinButton[2]) {
            two = "2";
        } else if(e.getSource() == pinButton[3]) {
            three = "3";
        } else if(e.getSource() == pinButton[4]) {
            four = "4";;
        } else if(e.getSource() == pinButton[5]) {
            five = "5";
        } else if(e.getSource() == pinButton[6]) {
            six = "6";
        } else if(e.getSource() == pinButton[7]) {
            seven = "7";
        } else if(e.getSource() == pinButton[8]) {
            eight = "8";
        } else if(e.getSource() == pinButton[9]) {
            nine = "9";
        }

        if(e.getSource() == enterBtn) {
            if(???.equals(pin)) {
                System.out.println("Correct");
            } else {
                System.out.println("Wrong");
            }
        }
}

Answer 1

有一个实例变量-

StringBuffer userKeyString = new StringBuffer();

执行操作后，附加按下的任何数字按钮-

userKeyString.append(event.getActionCommand());

执行操作时，如果按下 Enter 键 -

if(event.getSource() == enterBtn){

    if(pin.equals(userKeyString.toString()){

        // Correct pin

    } else {

        // Incorrect pin

    }

    userKeyString.setLength(0); // Clear the buffer for next input and validation

} else {

    userKeyString.append(event.getActionCommand());

}

您应该设置按钮的操作命令-

for(int i = 0; i < numberPinButton; i++) {
    pinButton[i] = new JButton("" + i);
    pinButton[i].setActionCommand(String.valueOf(i));
    pinButton[i].addActionListener(this);
    panel.add(pinButton[i]);
}