java - 如何在 java ee 6 框架中的 JAX-WS Web 服务中保存数据?

标签 java jakarta-ee jax-ws ejb-3.0 java-ee-6

我有一个使用 java ee 6 框架的 J2EE 项目。带有 EJB 和 War 模块。 我想向EJB模块添加一个Service来操作数据库中的一些数据,所以我需要访问Service方法中的DAO方法。但它返回错误!

@WebService(serviceName = "AddUserService")
@Stateless()
public class AddUserService {
   @PersistenceContext(unitName = "UserRegistrationService-ejbPU")
    EntityManager em;

    @WebMethod(operationName = "registerUser")
    public String registerUser(BasicUserInfo basicUserInfo) {
        UserEJB userEJB=new UserEJB(em);
        String retValue = "";
        User user = new User();
        user.setAge(basicUserInfo.getAge());
        user.setUserName(userName);
        userEJB.addUser(user);
        retValue = " User Registered with user_ID:" + user.getId().toString() + "  and userName:" + user.getUserName();
        return retValue;
    }
}

EJB 类代码是:

    @TransactionManagement(TransactionManagementType.CONTAINER)
@Stateless
public class UserEJB {

    @PersistenceContext(unitName = "UserRegistrationService-ejbPU")
    EntityManager em;

    public UserEJB() {
    }

    public UserEJB(EntityManager em) {
        this.em = em;
    }

    public void addUser(User user) {
        em.persist(user);
    }
}

测试服务会在服务器上出现此错误:

        at java.lang.Thread.run(Thread.java:619)
Caused by: java.lang.NullPointerException
    at dao.UserEJB.addUser(UserEJB.java:34)
    at app.Services.AddUserService.registerUser2(AddUserService.java:60)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
    at java.lang.reflect.Method.invoke(Method.java:597)
    at org.glassfish.ejb.security.application.EJBSecurityManager.runMethod(EJBSecurityManager.java:1052)
    at org.glassfish.ejb.security.application.EJBSecurityManager.invoke(EJBSecurityManager.java:1124)
    at com.sun.ejb.containers.BaseContainer.invokeBeanMethod(BaseContainer.java:5388)
    at com.sun.ejb.EjbInvocation.invokeBeanMethod(EjbInvocation.java:619)
    at com.sun.ejb.containers.interceptors.AroundInvokeChainImpl.invokeNext(InterceptorManager.java:800)
    at com.sun.ejb.EjbInvocation.proceed(EjbInvocation.java:571)
    at com.sun.ejb.containers.interceptors.SystemInterceptorProxy.doAround(SystemInterceptorProxy.java:162)
    at com.sun.ejb.containers.interceptors.SystemInterceptorProxy.aroundInvoke(SystemInterceptorProxy.java:144)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
    at java.lang.reflect.Method.invoke(Method.java:597)
    at com.sun.ejb.containers.interceptors.AroundInvokeInterceptor.intercept(InterceptorManager.java:861)

最佳答案

您的 EntityManger 不会被容器注入(inject),因为您自己创建了 UserEJB 对象!你已经破坏了注入(inject)链。使用 DI 时,您必须让容器为您创建对象。试试这个方法:

@WebService(serviceName = "AddUserService")
@Stateless()
public class AddUserService {

    //actually you don't need this here, you'll get that injected inside the UserEJB
    @PersistenceContext(unitName = "UserRegistrationService-ejbPU")
    EntityManager em;


    @Inject
    UserEJB userEjb;

    @WebMethod(operationName = "registerUser")
    public String registerUser(BasicUserInfo basicUserInfo) {
        //you don't need this line, the container will instantiate the object for you!
        //UserEJB userEJB=new UserEJB(em);
        String retValue = "";
        User user = new User();
        user.setAge(basicUserInfo.getAge());
        user.setUserName(userName);
        userEJB.addUser(user);
        retValue = " User Registered with user_ID:" + user.getId().toString() + "  and         userName:" + user.getUserName();
        return retValue;
    }
}

关于java - 如何在 java ee 6 框架中的 JAX-WS Web 服务中保存数据?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19049951/

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