我对如何实现 System.exit(0); 有点困惑在我的程序中。我想要发生的是用户输入“exit”一词并让程序终止。我还希望程序在输入“clear”时返回“0.0”，但我认为我在处理变量时遇到问题，因为 num1 和 num2 是 double ，但我希望“exit”和“clear”是可接受的输入，也是如此。
如果有人有任何见解，我们将不胜感激。这是我的代码:
package projectapcs;
/**
*
* @author Apple
*/
import java.util.Scanner;
public class ProjectAPCS {
public static void exit(int x){
}
public static void clear(int y){
}
public static void main(String[] args) {
double num1;
double num2;
char char1;
String operation;
Scanner input = new Scanner(System.in);
System.out.println
("Enter 'exit' to quit the calculator, 'help' for more options or 'continue' to use the calculator");
System.out.println
("\nEnter the first number:");
num1 = input.nextInt();
System.out.println
("Display:" + num1);
System.out.println("Please enter operation:");
operation = input.next();
System.out.println("Enter the second number:");
num2 = input.nextInt();
System.out.println ("Display:" + num2);
if ("+".equals(operation)){
System.out.println((num1 + num2));
}
else if ("-".equals(operation)){
System.out.println((num1 - num2));
}
else if ("/".equals(operation)){
System.out.println((num1 / num2));
}
else if ("*".equals(operation)){
System.out.println((num1 * num2));
}
else if ("-x".equals(operation)){
System.out.println (-num1);
}
else if ("x^2".equals(operation)){
System.out.println (num1 * num1);
}
else if ("sqrt".equals(operation)){
System.out.println (Math.sqrt(num1));
}
else if ("H".equals(num1)){
System.out.println("Type + for the addition of values");
System.out.println("Type - for the substraction of values");
System.out.println("Type * for the multiplcation of values");
System.out.println("Type / for the division of values");
System.out.println("Type negate for the negation of values");
System.out.println("Type ^2 for squaring of values");
}
else if("E".equals(num1)){
System.out.println ("Calculator program terminated...");
System.exit(0);
}
}
}
最佳答案
如果您想允许任意输入，请将输入读取为字符串，然后 convert to double根据需要:
String input = scanner.next();
if (input.equals("exit")) {
exit();
else if (input.equals("clear")) {
clear();
} else {
try {
double number = Double.parseDouble(input);
/* do something with `number` */
} catch (NumberFormatException e) {
System.err.println("Not a double.");
}
}
关于java - java中使用System.exit(0)退出程序，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/19308938/