我正在尝试编写一个 try catch block ,如果用户没有输入名称而只是按 enter
或 okay
我似乎有问题是因为它不会抛出任何内容,它只是接受空白并继续。有人能帮我吗?预先感谢!
这是函数:
public String setOwnerName() {
boolean isName = false;
while(!isName) {
try {
this.ownerName = JOptionPane.showInputDialog(null, "Enter the account owner's name.", "Owner's Name", JOptionPane.PLAIN_MESSAGE);
if(this.ownerName != "") {
isName = true;
}
} catch(IllegalArgumentException e) {
JOptionPane.showMessageDialog(null, "Error you did not enter a name, please try again.", "Error", JOptionPane.ERROR_MESSAGE);
}
}
return this.ownerName;
}
最佳答案
空名称不会引发异常
。您需要手动检查它。尝试一下,
public String setOwnerName() {
boolean isName = false;
while(!isName) {
ownerName = JOptionPane.showInputDialog(null, "Enter the account owner's name.",
"Owner's Name", JOptionPane.PLAIN_MESSAGE);
if(ownerName.trim().isEmpty()){
JOptionPane.showMessageDialog(null,
"Error you did not enter a name, please try again.",
"Error", JOptionPane.ERROR_MESSAGE);
}
else{
isName = true;
}
}// end of while
return ownerName;
}
关于java - 如果 JTextField 为空,则抛出错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20210464/