这是我的 JSP 文件。它有 3 个文本字段和一个提交按钮..
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<form action="buttontoserv" method="post">
<input type="text" name="name"/><br>
<input type="text" name="group"/>
<input type="text" name="pass"/>
<input type="submit" value="submit">
</form>
</body>
</html>
这是我的 web.xml
<?xml version="1.0" encoding="utf-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5">
<servlet>
<servlet-name>ButtontoServ</servlet-name>
<servlet-class>pack.exp.ButtontoServServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>ButtontoServ</servlet-name>
<url-pattern>/buttontoserv</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
</web-app>
这是pack.exp包下的servlet，文件名为ButtontoServServlet.java
package pack.exp;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.*;
@SuppressWarnings("serial")
public class ButtontoServServlet extends HttpServlet
{
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException
{
String name = request.getParameter("name");
String group = request.getParameter("group");
String pass = request.getParameter("pass");
System.out.println("Name :"+ name);
System.out.println("group :"+ group);
System.out.println("pass :"+ pass);
}
}
当我将其部署到谷歌应用程序引擎时，它抛出此错误 “错误:此 URL 不支持 HTTP 方法 GET”
我也在tomcat上尝试过，错误提示 “HTTPO 405 方法不允许。网站无法显示页面 HTTP 405 最可能的原因: •网站存在编程错误。”
最佳答案
因为您的 servlet 只有 doPost 方法。因此，您无法通过 URL 访问 servlet。您的 URL 应该是分配了 action="buttontoserv" 的 JSP 页面。当您单击 JSP 页面的提交按钮时，它将转发到 /buttontoserv servlet。
要解决您的问题，您应该在 Servlet 上包含一个 doGet 方法，或者通过从 JSP 页面提交表单转发到 Servlet。
public class ButtontoServServlet extends HttpServlet {
protected void processRequest(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
String name = request.getParameter("name");
String group = request.getParameter("group");
String pass = request.getParameter("pass");
System.out.println("Name :"+ name);
System.out.println("group :"+ group);
System.out.println("pass :"+ pass);
}
@Override
protected void doGet(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
processRequest(request, response);
}
@Override
protected void doPost(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
processRequest(request, response);
}
}
关于java - 我是 jsp 和 google 应用引擎的新手，收到此错误 : HTTP method GET is not supported by this URL，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/20487646/