将字符串放入单个数组很容易,但我想将字符串放入 2d char[][]; 我被困在这里,有人可以帮助我吗...谢谢你,很抱歉我的英语不好!
String woord = "GPDNATSFASELNIERTPOTSRARIRRCOOFPUAUOGONOTORENOTUAMRHRILGTPOFRSCENOIEKLMETANTRSRUNIAARSETEITNAKAVERNTEJLIBFTNVOTWEEDEKLASC";
char[][] bord = new char[11][11];
char[] letters = woord.toCharArray();
int teller = 0;
//Board into a single array
for (int i = 0; i < woord.length(); i++) {
letters[i] = woord.charAt(i);
teller++;
System.out.print(letters[i]);
if (teller % 11 == 0) {
System.out.println();
}
}
//Board into a 2d Array
for (int r = 0; r < bord.length; r++) {
bord[r][0]=letters[r]; //<=== first 11 letters, next?
System.out.print(bord[r][0]);
for (int c = 0; c < bord[0].length; c++) {
//??
}
}
最佳答案
您可以在遍历多维数组时使用常用的技巧。 r*11 + a
值(根据循环)将为我们提供字符串的下一个字符。下面的代码,
//Board into a 2d Array
for (int r = 0; r < bord.length; r++) {
for(int a = 0; a < 11; a++)
bord[r][a] = letters[r*11 + a];
System.out.println(bord[r]);
}
将给出输出:
GPDNATSFASE
LNIERTPOTSR
ARIRRCOOFPU
AUOGONOTORE
NOTUAMRHRIL
GTPOFRSCENO
IEKLMETANTR
SRUNIAARSET
EITNAKAVERN
TEJLIBFTNVO
TWEEDEKLASC
关于java - 将字符串放入二维数组中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21581742/