我有一个 json 文件，其中保存了特定 channel 的时间表。现在，我想使用 gson 将 string 转换为 java 对象。我知道这很简单，但是我对字符串的结构感到困惑。这是我的 JSON 字符串的格式:
{
"date": "28022014",
"channelName": "star-movies",
"listOfShows": [
{
"showTitle": "Pirates of the Caribbean: The Curse of the Black Pearl",
"showTime": "01:30:00",
"showThumb": "http://tv.burrp.com/images/s/v/v/vv71wogh_644_4_140.jpg",
"showDetails": {
"IMDB Rating": "8.0/10",
"Nominated For": "Bafta Film Award Best Performance by an Actor in 2004: Johnny Depp, Best Sound in 2004: Christopher Boyes; George Watters II, Best in Special Visual Effects: John Knoll; Hal T. Hickel",
"Trivia": "The movie is inspired by, and takes its theme from, the popular Walt Disney theme park ride of the same name.",
"Produced By": "Jerry Bruckheimer",
"Directed By": "Gore Verbinski",
"Show Type:": "Movie",
"Followed By": "Pirates of the Caribbean: Dead Man\u0027s Chest",
"Written By": "Ted Elliott, Terry Rossio",
"Language:": "English",
"Repeats on:": "Sun, Feb 23 11:30PM Tue, Feb 25 7:00AM Wed, Feb 26 2:00PM",
"Music By": "Klaus Badelt",
"Release Date": "9 July 2003",
"Cast": "Johnny Depp, Geoffrey Rush, Orlando Bloom, Keira Knightley, Jack Davenport",
"Genre:": "Action/Adventure Sci-Fi/Fantasy",
"Show Description": "The Governor\u0027s beautiful daughter Elizabeth (Keira Knightley) is kidnapped by the evil Captain Barbossa (Geoffrey Rush). At that point, Will Turner (Orlando Bloom), her would-be suitor, seeks the help of Captain Jack Sparrow (Johnny Depp), a notorious conman. But then, Jack has his own reasons for hunting down Barbossa and his crew. They have stolen Sparrow\u0027s ship, The Black Pearl."
}
},
{
"showTitle": "Fillers",
"showTime": "03:30:00",
"showThumb": "http://tv.burrp.com/images/s/e/i/eims7nmh_1fwv_1_75.jpg",
"showDetails": {
"Repeats on:": "Sat, Feb 22 1:29AM Mon, Feb 24 3:30AM Tue, Feb 25 2:30AM",
"Language:": "English",
"Show Type:": "Promo/Filler",
"Show Description": "It\u0027s a series featuring film based program."
}
},
....
...
}]
}
这是我提出的类结构:
public class ChannelSchedule {
private String date;
private String channelName;
private List<Show> listOfShows;
public String getDate() {
return date;
}
public void setDate(String date) {
this.date = date;
}
public String getChannelName() {
return channelName;
}
public void setChannelName(String channelName) {
this.channelName = channelName;
}
public List<Show> getListOfShows() {
return listOfShows;
}
public void setListOfShows(List<Show> listOfShows) {
this.listOfShows = listOfShows;
}
}
public class Show {
private String showTitle;
private String showTime;
private String showThumb;
public String getShowThumb() {
return showThumb;
}
public void setShowThumb(String showThumb) {
this.showThumb = showThumb;
}
public String getShowTitle() {
return showTitle;
}
public void setShowTitle(String showTitle) {
this.showTitle = showTitle;
}
public String getShowTime() {
return showTime;
}
public void setShowTime(String showTime) {
this.showTime = showTime;
}
}
我无法弄清楚如何在列表中对象化 showDetails ？因为它的键值对之间有空格......？我在这里错过了什么吗？或者有解决方法吗？
最佳答案
你有两个选择；
看起来像showDetails里面可以有很多不同的东西。如果您知道它们是什么，您可以列出所有可能的情况:
public class ShowDetails {
@SerializedName("IMDB Rating")
String imdbRating;
@SerializedName("Repeats on:")
String repeatsOn;
// etc , etc
}
然后将其添加到您的 Show 中类:
...
ShowDetails showDetails;
...
但这可能有点疯狂，具体取决于可以有多少东西，或者如果您不知道所有可能性是什么。选项 B 更简单，使用 Map<String, String> :
public class Show {
private String showTitle;
private String showTime;
private String showThumb;
private Map<String, String> showDetails;
// ...
}
JSON 中的键/值对将作为...键/值对放入映射中。
关于java - 无法使用 GSON 将 JSON 字符串转换为 JAVA 对象，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/22089667/