我正在创建一个应用程序,此时需要从 sqlite 数据库获取文件名,获取具有该文件名的图像并将其插入 ImageView 中,我现在已经创建了此代码,但我认为我'我在这里做的一切都错了......
Database db = new Database(getApplicationContext());
SQLiteDatabase readableDatabase = db.getReadableDatabase();
final Cursor curFileName = readableDatabase.rawQuery("select filename from data order by id asc", null);
image = (ImageView) findViewById(R.id.image);
int filename = curFileName.getColumnIndex("filename");
String filenameString = curFileName.getString(filename);
d = Drawable.createFromPath(Environment.getExternalStorageDirectory().toString()+filenameString);
Toast.makeText(getApplicationContext(), filenameString, Toast.LENGTH_SHORT).show();
handleDrawable(d);
是的,抱歉,这是异常(exception):
04-09 13:48:16.950: E/AndroidRuntime(30802): FATAL EXCEPTION: main
04-09 13:48:16.950: E/AndroidRuntime(30802): java.lang.RuntimeException: Unable to start activity ComponentInfo{g.d.filer/g.d.filer.Favorites}: android.database.CursorIndexOutOfBoundsException: Index -1 requested, with a size of 33
最佳答案
您必须先定位光标才能阅读
int filename = curFileName.getColumnIndex("filename");
if (cur.moveToFirst()) { // position cursor to first item. false: empty resultset
String filenameString = curFileName.getString(filename);
d = Drawable.createFromPath(Environment.getExternalStorageDirectory().toString()+filenameString);
Toast.makeText(getApplicationContext(), filenameString, Toast.LENGTH_SHORT).show();
handleDrawable(d);
...
}
关于java - 从数据库获取文件名并使用它来填充 ImageView,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22961806/