java - HQL 可完美运行嵌套 SQL

Question

任何人都可以帮助为下面完美运行的 SQL 查询编写 HQL 查询吗

select d2.user_id,d2.push_token,d2.registration_date from device_registration d2,(
select max(d1.registration_date) as registration_date,d1.push_token from device_registration d1
where  d1.push_Token != 'null' and d1.push_Token is not null and d1.push_Token!=''
group by d1.push_token) d3
where d2.push_token=d3.push_token and d2.registration_date=d3.registration_date 
order by d2.registration_date asc

Answer 1

这是查询，稍微重新格式化:

select d2.user_id, d2.push_token, d2.registration_date
from device_registration d2 join
     (select max(d1.registration_date) as registration_date, d1.push_token
      from device_registration d1
      where d1.push_Token <> 'null' and d1.push_Token is not null and d1.push_Token <> ''
      group by d1.push_token
     ) d3
     on d2.push_token = d3.push_token and d2.registration_date = d3.registration_date 
order by d2.registration_date asc;

它本质上是获取每个push_token的最长注册日期。以下内容应遵循 HQL 标准:

select 2.*
from device_registration d
where not exists (select 1
                  from device_registration d2
                  where d2.push_token = d.push_token and d2.registration_date > d.registration_date
                 )
order by d.registration_date desc;