我一直在编写 Android 应用程序,但遇到了一些问题。我尝试使用寻呼机适配器扩展类(参见下面的代码)来实现教程,并制作一些背景壁纸来显示应用程序的工作原理。现在,您可以在屏幕上滑动手指,从一页转到另一页。我想通过触摸来改变屏幕。那可能吗?如果可以,该怎么办?我想这可能是通过使用 onClick 方法。
提前致谢,对我的英语表示抱歉。
教程.java
public class tutorial extends Activity {
int currentPage;
@Override
public void onCreate(Bundle savedInstanceState){
super.onCreate(savedInstanceState);
//Remove title bar
this.requestWindowFeature(Window.FEATURE_NO_TITLE);
//set content view AFTER ABOVE sequence (to avoid crash)
this.setContentView(R.layout.tutorial_pannels_pager);
MyPagerAdapter adapter = new MyPagerAdapter();
final ViewPager myPager = (ViewPager) findViewById(R.id.tutorial_pannel);
myPager.setAdapter(adapter);
myPager.setCurrentItem(0);
}
}
MyPagerAdapter.java
public class MyPagerAdapter extends PagerAdapter {
// set number of pages
@Override
public int getCount() {
// TODO Auto-generated method stub
return 7;
}
// Set each screen's content
@Override
public Object instantiateItem(final View container, final int position) {
Context context = container.getContext();
LinearLayout layout = new LinearLayout(context);
// Add elements
TextView textItem = new TextView(context);
switch (position) {
case 0:
layout.setBackgroundResource(R.drawable.tut_0);
break;
case 1:
layout.setBackgroundResource(R.drawable.tut_1);
break;
case 2:
layout.setBackgroundResource(R.drawable.tut_2);
break;
case 3:
layout.setBackgroundResource(R.drawable.tut_3);
break;
case 4:
layout.setBackgroundResource(R.drawable.tut_4);
break;
case 5:
layout.setBackgroundResource(R.drawable.tut_5);
break;
case 6:
layout.setBackgroundResource(R.drawable.tut_6);
break;
}
layout.addView(textItem);
((ViewPager) container).addView(layout, 0); // This is the line I added
return layout;
}
@Override
public void destroyItem(View arg0, int arg1, Object arg2) {
((ViewPager) arg0).removeView((View) arg2);
}
@Override
public boolean isViewFromObject(View arg0, Object arg1) {
return arg0 == ((View) arg1);
}
@Override
public Parcelable saveState() {
return null;
}
}
tutorial_pannels_pager.xml
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:gravity="bottom"
android:orientation="vertical" >
<android.support.v4.view.ViewPager
android:layout_width="match_parent"
android:layout_height="match_parent"
android:id="@+id/tutorial_pannel"/>
</LinearLayout>
最佳答案
首先,您必须将接口(interface)传递给适配器。这个例子应该会给你启发:
public interface OnItemClick{
void onClick(int position);
}
接下来您应该实现此接口(interface)并添加代码以手动更改 View 。接下来将此接口(interface)的实例传递给适配器。像这样:
MyPagerAdapter adapter = new MyPagerAdapter(new OnItemClick(){
@Override
public void onClick(int position)
{
myPager.setCurrentItem(position+1); //example.. change it to your needs
}
});
接下来,在您的适配器上,您需要将一个实例保存到构造函数中传递的此接口(interface),然后在单击布局时调用它。
layout.setOnClickListener(new View.OnClickListener()
{
@Override
public void onClick(View view)
{
interface.onClick(position);
}
});
这只是基础知识,您需要自己解决。然而,这是达到最终解决方案所必需的。
干得好。
关于java - Android 寻呼机适配器,onClick,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25977183/