我试图按照互联网上的一些示例来了解 Spring 登录系统的工作原理。我面临着很多困难。我最新的问题是，即使我正确输入用户名和密码(它们在 security-config.xml 中设置)，我也会被重定向到登录页面。
这就是我到目前为止所做的(我将只向您展示相关代码)。
安全配置.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xsi:schemaLocation="
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd">
<http use-expressions="true">
<intercept-url pattern="/login*" access="isAnonymous()" />
<intercept-url pattern="/**" access="isAuthenticated()"/>
<form-login
login-page='/login'
default-target-url="/profile"
authentication-failure-url="/login?error=true" />
<logout logout-success-url="/login" />
</http>
<authentication-manager>
<authentication-provider>
<user-service>
<user name="user1" password="user1Pass" authorities="ROLE_USER" />
</user-service>
</authentication-provider>
</authentication-manager>
</beans:beans>
web.xml
<web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemalocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5">
<display-name>Sample Spring Maven Project</display-name>
<servlet>
<servlet-name>mvc-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/mvc-dispatcher-servlet.xml,
/WEB-INF/security-config.xml
</param-value>
</context-param>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>
这是我的 Controller
import org.springframework.stereotype.Controller;
import org.springframework.ui.Model;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestParam;
@Controller
public class LoginController {
@RequestMapping("/login")
public String getLoginForm(Model model, @RequestParam(required = false) String error, String logout) {
if (error != null) {
model.addAttribute("message", "Invalid username of password, try again !");
} else if (logout != null) {
model.addAttribute("message", "Logged Out successfully, login again to continue !");
}
return "login";
}
@RequestMapping("/profile")
public String geProfilePage() {
return "profile";
}
}
登录.jsp
<%@taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%>
<html>
<head>
<title></title>
</head>
<body>
<center>
<div
style="text-align: center; padding: 30px; border: 1px solid green; width: 250px;">
<form method="post"
action="<c:url value='j_spring_security_check' />">
<table>
<tr>
<td colspan="2" style="color: red">${message}</td>
</tr>
<tr>
<td>User Name:</td>
<td><input type="text" name="username" /></td>
</tr>
<tr>
<td>Password:</td>
<td><input type="password" name="password" /></td>
</tr>
<tr>
<td> </td>
<td><input type="submit" value="Login" /></td>
</tr>
</table>
</form>
</div>
</center>
</body>
</html>
最佳答案
由于/login 请求在 Controller 中返回“登录”
关于java - Spring登录表单不起作用，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/26259513/