我正在学习 spring-mvc,我使用 STS 创建了一个 CRUD 项目,并且运行良好。
我需要创建另一个 View 只是为了测试和使用 spring:
- 我在与其他 jsp 文件 (WEB-INF/views) 相同的位置添加了一个新的 jsp 文件,名为 company.jsp
- 我创建了一个新 Controller 来处理请求:
package com.test.issa; import org.springframework.stereotype.Controller; import org.springframework.ui.Model; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.bind.annotation.RequestMethod; @Controller public class CompanyController { @RequestMapping(value = "/company", method = RequestMethod.GET) public String GetCompany(Model model) { model.addAttribute("name", "Hello World!"); return "company"; } }
但是当我调用 View http://localhost:9999/app/company 时,它给出错误 404,我是否遗漏了什么?
这也是我的 servlet-context.xml:
<?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-4.0.xsd">
<!-- DispatcherServlet Context: defines this servlet's request-processing
infrastructure -->
<!-- Enables the Spring MVC @Controller programming model -->
<annotation-driven />
<!-- Handles HTTP GET requests for /resources/** by efficiently serving
up static resources in the ${webappRoot}/resources directory -->
<resources mapping="/resources/**" location="/resources/" />
<!-- Resolves views selected for rendering by @Controllers to .jsp resources
in the /WEB-INF/views directory -->
<beans:bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
</beans:bean>
<!-- Hibernate 4 SessionFactory Bean definition -->
<beans:bean id="hibernate4AnnotatedSessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<beans:property name="dataSource" ref="dataSource" />
<beans:property name="annotatedClasses">
<beans:list>
<beans:value>com.journaldev.spring.model.Person</beans:value>
</beans:list>
</beans:property>
<beans:property name="hibernateProperties">
<beans:props>
<beans:prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect
</beans:prop>
<beans:prop key="hibernate.show_sql">true</beans:prop>
</beans:props>
</beans:property>
</beans:bean>
<beans:bean id="personDAO" class="com.journaldev.spring.dao.PersonDAOImpl">
<beans:property name="sessionFactory" ref="hibernate4AnnotatedSessionFactory" />
</beans:bean>
<beans:bean id="personService" class="com.journaldev.spring.service.PersonServiceImpl">
<beans:property name="personDAO" ref="personDAO"></beans:property>
</beans:bean>
<context:component-scan base-package="com.journaldev.spring" />
<tx:annotation-driven transaction-manager="transactionManager"/>
<beans:bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<beans:property name="sessionFactory" ref="hibernate4AnnotatedSessionFactory" />
</beans:bean> </beans:beans>
最佳答案
您只是扫描此处声明的包的组件
<context:component-scan base-package="com.journaldev.spring" />
但是你的@Controller
定义于
package com.test.issa;
您需要将该包添加到 component-scan
,否则不会为 @Controller
创建 bean带注释的类型,MVC 堆栈不会注册其处理程序方法。
要么声明一个显式 <bean>
为您CompanyController
类型。
关于java - Spring MVC - 无法渲染 View ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27155008/