Java 将字符串拆分为 Pig Latin 翻译器的单个单词

Question

我有一个单字 Pig Latin 翻译器，我需要它来

• 翻译包含多个单词的字符串
• 适当大写
• 正确标点(非字母字符。即 astah, = astahay，而不是 astah,ay)

我用来测试的单词/字符串是“Astah la vista，宝贝”。其输出应为“Astahay alay istavay, abybay。”

此代码仅正确翻译一个单词字符串，并且不能正确地大写/标点符号。 我的程序使用 3 个方法，input()、pigLatinator() 和 display() 来输入字符串、翻译并显示翻译。 有了这个结构，我可以改变/添加什么来使这个程序更接近我想要的方式工作？我看过使用 String.split("\\s") 但我不明白如何实现它。

输入法:

    public String input(){
    System.out.println("Please enter your string.");
    System.out.print("String: ");
    originalString = keyboard.nextLine();
    originalString = originalString.toLowerCase(); //String.toLowerCase() to prevent error on line 41 (if() statement)

    return originalString;
}

pigLatinator 方法:

    public String pigLatinator(String originalString){
    if(originalString.startsWith("a") || originalString.startsWith("e") || originalString.startsWith("i") || originalString.startsWith("o") || originalString.startsWith("u")){
        pigString = originalString + "ay";
    }else{
        pigString = originalString.substring(1) + originalString.charAt(0) + "ay";
    }

    return pigString;
}

显示方法:

public void display(){
    System.out.println();
    System.out.println("Original string: " +originalString);
    System.out.println("Translation: " +pigString);
}

输出:

输出1:

Please enter your string.
String: astah

Original string: astah
Translation: astahay

作品

输出2:

Please enter your string.
String: Astah

Original string: astah
Translation: astahay

输出3:

Please enter your string.
String: astah,

Original string: astah,
Translation: astah,ay

输出4:

Please enter your string.
String: Astah la vista, baby.

Original string: astah la vista, baby.
Translation: astah la vista, baby.ay

Answer 1

您可以使用String.split函数将输入句子拆分为单个单词。这是第一步，如下所示:

String[] words = originalString.split(" ");
String[] pigWords;

完成此操作后，您可以循环每个单词来更改它:

pigWords = new String[words.length];
for (int i = 0; i < words.length; i++)
    pigWords[i] = pigLatinator(words[i])

然后，修改pigLatinator以检查单词结尾是否有标点符号，并在标点符号之前插入“ay”:

int index = originalString.length() -1;
char lastChar = originalString.charAt(index);
if (char == "." || char == ",")
    String pigString = originalString.substring(0,index) + "ay" + originalString.charAt(index);

由于您的 PigLatin 类是一个独立于您的 main 类的类，因此您应该能够执行以下操作:

class PigLatin
{
    String originalString = "", pigString = "";

    public void input() {
        System.out.println("Please enter your string.");
        System.out.print("String: ");
        originalString = keyboard.nextLine().toLowerCase();
    }

    private String pigLatinator(String word)
    {
        String output = "";
        int index = word.length() -1;
        char lastChar = word.charAt(index);

        if(word.startsWith("a") || word.startsWith("e") || word.startsWith("i") || word.startsWith("o") || word.startsWith("u"))
        {
            if (char == '.' || char == ',' || char == '!')
                output = word.substring(0,index) + "ay" + word.charAt(index);
            else
                output = word + "ay";
        }
        else
        {
            if (char == '.' || char == ',' || char == '!')
                output = word.substring(1,index) + word.charAt(0) + "ay" + word.charAt(index);
            else
                output = word.substring(1) + word.charAt(0) + "ay";
        }

        return output;
    }

    public void translate()
    {
        String[] words = originalString.split(" ");
        for (int i = 0; i < words.length; i++)
        {
            pigString += pigLatinator(words[i]) + " ";
        }
    }

    public void display()
    {
        System.out.println();
        System.out.println("Original string: " +originalString);
        System.out.println("Translation: " +pigString);
    }
}

然后，在您的 main 函数中，声明一个新的 PigLatin 对象，并调用相应的函数:

public static void main(String[] args)
{
    PigLatin myPigLatin = new PigLatin();
    myPigLatin.input();
    myPigLatin.translate();
    myPigLatin.display();
}

此代码未经测试，但应该可以工作，而且很简单。