java - HTTP Status 404. 翻页后不显示数据

Question

我从 http://www.javacodegeeks.com/2014/03/building-java-web-application-using-hibernate-with-spring.html 导入项目 我试图找出原因，但仍然不知道为什么单击注册按钮后不显示页面注册。它不会在控制台中显示任何错误。项目使用Spring和Hibernate编写web登录和注册。

Controller .java

@Controller
@SessionAttributes("student")
public class StudentController {

    @Autowired
    private StudentService studentService;

    @RequestMapping(value="/signup", method=RequestMethod.GET)
    public String signup(Model model) {
        Student student = new Student();        
        model.addAttribute("student", student);     
        return "signup";
    }

    @RequestMapping(value="/signup", method=RequestMethod.POST)
    public String signup(@Valid @ModelAttribute("student") Student student, BindingResult result, Model model) {        
        if(result.hasErrors()) {
            return "signup";
        } else if(studentService.findByUserName(student.getUserName())) {
            model.addAttribute("message", "User Name exists. Try another user name");
            return "signup";
        } else {
            studentService.save(student);
            model.addAttribute("message", "Saved student details");
            return "redirect:login.html";
        }
    }

index.jsp

<a class="btn btn-primary" href="signup.html">Signup» </a> 

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

<servlet>
    <servlet-name>studentHibernateServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/config/servletConfig.xml</param-value>
    </init-param>
</servlet>

<servlet-mapping>
    <servlet-name>studentHibernateServlet</servlet-name>
    <url-pattern>*.html</url-pattern>
</servlet-mapping>

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>classpath:/jpaContext.xml</param-value>
</context-param>

<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

  <display-name>Archetype Created Web Application</display-name>
</web-app>

总是和下图一样

Answer 1

<servlet-mapping>与 <url-pattern>*.html</url-pattern>只需将所有以“html”结尾的请求定向到您的 StudentHibernateServlet。它不会将 *.jsp 翻译为 *.html。

您需要将 View 解析器添加到 web.xml 中，以将请求映射到 View 。如果您的signup.jsp 保存到WEB-INF 文件夹，您可以使用下面的xml。

<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">     
  <property name="prefix">
    <value>/WEB-INF/</value>
  </property>
  <property name="suffix">
    <value>.jsp</value>
  </property>
</bean>

您可能需要替换<url-pattern>*.html</url-pattern>与 <url-pattern>/</url-pattern>为了 View 名称 "signup"由您的 servlet 获取。

进行这些更改后，您的调度程序 servlet 将处理 "signup" 的请求通过附加指定的前缀和后缀，即 /WEB-INF/singup.jsp ，然后可以解析为实际 View 。