尝试创建一个将 RGB 颜色代码转换为其等效的十六进制代码的代码。到目前为止，我只完成了前两个字符的 if 语句，但收到错误:
ToHex.java:62:错误:变量digitOne可能尚未初始化 System.out.println("前两个字符是:"+digitOne+digitTwo); ^ ToHex.java:62:错误:变量digitTwo可能尚未初始化 System.out.println("前两个字符是:"+digitOne+digitTwo);
这是到目前为止我的代码的主要部分:
try{
int red, green, blue;
System.out.print("Please enter three numbers representing RGB values: ");
red = myScanner.nextInt();
green = myScanner.nextInt();
blue = myScanner.nextInt();
if(red>=0 && red<=255 && green>=0 && green<=255 && blue>=0 && blue<=255){
int firsthexRed = (int)(red/16);
int redremainder = red%16;
int firsthexGreen = (int)(green/16);
int greenremainder = green%16;
int firsthexBlue = (int)(blue/16);
int blueremainder = blue%16;
String digitOne, digitTwo, digitThree, digitFour, digitFive, digitSix;
if(firsthexRed>=0 && firsthexRed<=9){ //if statement for first hex character
digitOne = Integer.toString(firsthexRed);
}else if (firsthexRed==10){
digitOne = "A";
}else if (firsthexRed==11){
digitOne = "B";
}else if (firsthexRed==12){
digitOne = "C";
}else if (firsthexRed==13){
digitOne = "D";
}else if (firsthexRed==14){
digitOne = "E";
}else if (firsthexRed==15){
digitOne = "F";
}
if(redremainder>=0 && redremainder<=9){ //if statement for second hex character
digitTwo = Integer.toString(redremainder);
}else if (redremainder==10){
digitTwo = "A";
}else if (redremainder==11){
digitTwo = "B";
}else if (redremainder==12){
digitTwo = "C";
}else if (redremainder==13){
digitTwo = "D";
}else if (redremainder==14){
digitTwo = "E";
}else if (redremainder==15){
digitTwo = "F";
}
System.out.println("The first two characters are: "+digitOne+digitTwo);
}else{
System.out.println("You did not enter integers between 0-255 (inclusive).");
}
}catch(RuntimeException ex){
System.out.println("Sorry, your input must consist of integers.");
}
}
} ^ ^
最佳答案
不用担心，我所要做的就是将最后一个 else if 语句更改为 else 语句，以便编译器知道 digitalOne、digitTwo 将始终等于某个值。
关于java - 错误: Variable might not have been initialized?，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/28709744/