我正在使用 Java 尝试在服务器端检查用户发送的内容是否在 HashMap 中,但我的示例将以我给出的名称运行,无论它是否在 HashMap 中或不是。
有人知道为什么会发生这种情况吗?
客户端
package examPrep;
import java.io.InputStream;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.net.InetAddress;
import java.net.Socket;
import java.util.Scanner;
public class Client
{
public static String name;
public static void main(String[] args) throws Exception
{
//Client looks for the IP address of the server it wants
InetAddress inet = InetAddress.getByName("localhost");
//Creates a new socket connection on port 2021
Socket s = new Socket(inet, 2021);
///Associates a scanner with the Input stream
InputStream in = s.getInputStream();
//Creates a scanner that looks for input, returns false if there is no more
Scanner scanner = new Scanner(in);
//Associates a PrintWriter to the OutputStream
OutputStream o = s.getOutputStream();
PrintWriter p = new PrintWriter(o);
Scanner userInput = new Scanner(System.in);
//Using system input to put data across
System.out.println("Enter a username");
name = userInput.nextLine();
System.out.println("You typed in: " + name);
p.println(name);
//flush forces data to be sent even if the buffer is not full
p.flush();
//Reads the response and finishes
String inputLine = scanner.nextLine();
System.out.println("Client: " + inputLine);
}
}
服务器
package examPrep;
import java.io.InputStream;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.net.ServerSocket;
import java.net.Socket;
import java.util.HashMap;
import java.util.Scanner;
public class Server
{
public static void main(String[] args) throws Exception
{
HashMap<String, String> map = new HashMap<String, String>();
String name = "Billy";
String password = "1234";
map.put(name, password);
//creates a new socket
Socket s;
//Socket is listening on port 2000
ServerSocket ss = new ServerSocket(2021);
//Constantly checking the connection
while (true)
{
System.out.println("Server: waiting for connection ..");
//Ready to accept a connection
s = ss.accept();
//Associates a scanner with the Input stream
InputStream in = s.getInputStream();
Scanner r = new Scanner(in);
//Associates a PrintWriter to the OutputStream
OutputStream o = s.getOutputStream();
PrintWriter p = new PrintWriter(o);
//Writes to the socket
String inputLine;
inputLine = r.nextLine();
//This will always send the string back to the client
//regardless of whether its in the hashmap or not
if(inputLine == map.get(name))
{
// sends the String back to the client
p.println("Hello " + inputLine);
}
else
System.out.println("User " + inputLine + " not authorized");
//Connection is closed with the client when finished
p.close();
}
}
}
最佳答案
难以置信:实际上不可能。
更准确的说法是,无论名称是否在 HashMap 中,您的客户端都会失败,并出现 NoSuchElementException
。
其原因是对您的应用程序协议(protocol)完全混淆。客户端正在发送它认为是名称的内容,但服务器正在根据固定名称的密码对其进行检查。您的服务器代码应该使用 map.containsKey(inputLine)
来查找名称,而不是 Map.get(name)
。
在您尚未编码的后续交换中,客户端将发送密码,服务器应使用 map.get()
检索密码,并且应使用 .equals()
来比较字符串,而不是 ==
。
关于java - 检查某个元素是否在客户端和服务器之间的 HashMap 中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28733291/