我使用Java编程语言创建一对一的聊天应用程序 我遇到问题:客户端在收到来自服务器的消息之前无法发送新消息。
最佳答案
您应该有一个多线程应用程序。 客户端将运行2个线程: 1) 将在发送按钮上运行的发送者线程。您每次都可以通过单击“发送”按钮创建该线程的新实例。 2) 接收线程将继续持续运行并检查流中是否有任何消息。一旦它在流上收到消息,它就会在控制台上写入相同的消息。
很快就会向您更新代码。 谢谢
很久以前就写过这段代码,类似地,您可以使用其他端口编写服务器
package com.clients;
import java.awt.BorderLayout;
import java.awt.GridLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.awt.event.WindowAdapter;
import java.awt.event.WindowEvent;
import java.awt.event.WindowListener;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.net.Socket;
import java.net.UnknownHostException;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.JScrollPane;
import javax.swing.JTextArea;
import javax.swing.JTextField;
public class ClientFullDuplex extends JFrame implements ActionListener {
private JFrame jframe;
private JPanel jp1, jp2;
private JScrollPane jsp;
private JTextArea jta;
private JTextField jtf;
private JButton send;
private Thread senderthread;
private Thread recieverthread;
private Socket ds;
private boolean sendflag;
public static void main(String[] args) {
try {
ClientFullDuplex sfd = new ClientFullDuplex();
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public ClientFullDuplex() throws UnknownHostException, IOException {
initGUI();
ds = new Socket("127.0.0.1", 1124);
initNetworking();
}
public void initGUI() {
jframe = new JFrame();
jframe.setTitle("Client");
jframe.setSize(400, 400);
jp1 = new JPanel();
jta = new JTextArea();
jsp = new JScrollPane(jta);
jtf = new JTextField();
send = new JButton("Send");
send.addActionListener(this);
jp1.setLayout(new GridLayout(1, 2, 10, 10));
jp1.add(jtf);
jp1.add(send);
jframe.add(jp1, BorderLayout.SOUTH);
jframe.add(jsp, BorderLayout.CENTER);
jframe.setVisible(true);
jframe.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
jta.append("hello client");
}
@Override
public synchronized void addWindowListener(WindowListener arg0) {
// TODO Auto-generated method stub
super.addWindowListener(arg0);
new WindowAdapter() {
@Override
public void windowClosing(WindowEvent arg0) {
// TODO Auto-generated method stub
if (ds != null)
try {
ds.close();
System.exit(0);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
};
}
public void initNetworking() {
try {
recieverthread = new Thread(r1);
recieverthread.start();
} catch (Exception e) {
e.printStackTrace();
}
}
Runnable r1 = new Runnable() {
@Override
public void run() {
try {
System.out.println(Thread.currentThread().getName()
+ "Reciver Thread Started");
recieveMessage(ds);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
};
Runnable r2 = new Runnable() {
@Override
public void run() {
try {
System.out.println(Thread.currentThread().getName()
+ "Sender Thread Started");
sendMessage(ds);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
};
public void recieveMessage(Socket rms) throws IOException {
while (true) {
System.out.println(Thread.currentThread().getName()
+ "Reciver Functionality");
BufferedReader br = new BufferedReader(new InputStreamReader(
rms.getInputStream()));
String line = br.readLine();
System.out.println(line);
jta.append("\nServer:"+line);
}
}
public void sendMessage(Socket sms) throws IOException {
System.out.println(Thread.currentThread().getName()
+ "Sender Functionality");
PrintWriter pw = new PrintWriter(sms.getOutputStream(), true);
String sline = jtf.getText();
System.out.println(sline);
pw.println(sline);
jtf.setText("");
}
@Override
public void actionPerformed(ActionEvent e) {
// TODO Auto-generated method stub
if (e.getSource() == send) {
senderthread = new Thread(r2);
senderthread.start();
}
}
}
关于Java套接字: how the server can reads multiple lines from the client,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28875548/