我正在为一个相当简单的棋盘游戏制作我的第一个 GUI。除了游戏 View 之外,我还需要主菜单和其他一些 View 。不幸的是,我的 GUI 看起来比早上更难看,因为整个菜单结构都在一个类中。我使用卡片布局在不同 View 之间切换,所以我想我可以将这些 View 分成不同的类。可悲的是,这就是我遇到问题的地方。我得到的只是一个空白窗口。
经过四个小时的研究,我还没能解决我的问题,所以我问你们,你们知道我的代码有什么问题吗?即使很困难,我认为我已经排除了明显的问题(没有使用卡片布局将面板添加到我的面板中,没有设置布局等),我仍然认为问题一定是非常简单的。但我发现没有任何帮助。
对于企业来说,这是我的“基本 GUI”
package teekkariloikka.gui;
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
public class TLGui extends JFrame {
private static final long serialVersionUID = 1L;
private static final int WIDTH = 1000;
private static final int HEIGHT = 800;
private static final String MAINMENU = "mainmenu";
private static final String GAME = "game";
private JPanel basePanel;
private GameViewPanel gameViewPanel;
private MainMenuPanel mainMenuPanel;
JFrame frame = new JFrame();
//Layout
private CardLayout cardL = new CardLayout();
public TLGui(){
//Frame stuff
frame.setTitle("Teekkariloikka");
frame.setSize(WIDTH, HEIGHT);
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setVisible(true);
frame.setResizable(false);
//This is the panel where I add the ohter panels for menu and game
basePanel = new JPanel();
basePanel.setLayout(cardL);
//Creating the panels I want to add. Excuse the confusing naming.
gameViewPanel = new GameViewPanel();
mainMenuPanel = new MainMenuPanel();
//Adding the panels to the basePanel
basePanel.add(mainMenuPanel, MAINMENU);
basePanel.add(gameViewPanel, GAME);
cardL.show(basePanel, MAINMENU);
//ADDING basePanel to the frame
frame.add(basePanel);
//Action listeners for buttons. Take a look at the classes.
mainMenuPanel.setNewGameButtonListener(new ActionListener(){
@Override
public void actionPerformed(ActionEvent e){
cardL.show(basePanel, GAME);
}
});
gameViewPanel.setMainMenuButtonListener(new ActionListener(){
@Override
public void actionPerformed(ActionEvent e){{
cardL.show(basePanel, MAINMENU);
}
});
}
public static void main(String[] args){
SwingUtilities.invokeLater(new Runnable() {
@Override
public void run(){
new TLGui();
}
});
}
}
然后是我的 MainMenuPanel 类。这是一项正在进行的工作,但至少应该显示按钮。我尽了最大努力翻译我用芬兰语(我的母语)写的所有内容,我真的希望我不会对我的代码视而不见,以至于忘记了一些东西。
package teekkariloikka.gui;
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
public class MainMenuPanel extends JPanel{
private static final long serialVersionUID = 1L;
//Buttons
private JPanel panel;
private JButton newGameButton;
private JButton quitButton;
//Font
Font menuFont = new Font("Arial", Font.BOLD, 24);
//Layout
private GridBagLayout menuLayout = new GridBagLayout();
private GridBagConstraints c1 = new GridBagConstraints();
public MainMenuPanel(){
panel = new JPanel();
//For testing //TODO remove
panel.setBackground(Color.BLACK);
newGameButton = new JButton("New Game");
quitButton = new JButton("Quit");
//New Game -button
newGameButton.setPreferredSize(new Dimension(200, 100));
newGameButton.setFont(menuFont);
//Quit-button
quitButton.setPreferredSize(new Dimension(200, 100));
quitButton.setFont(menuFont);
panel.setLayout(menuLayout);
c1.insets = new Insets(10, 10, 10, 10);
c1.gridx = 0;
c1.gridy = 1;
panel.add(newGameButton, c1);
c1.gridx = 0;
c1.gridy = 2;
panel.add(quitButton, c1);
}
//Idea: http://stackoverflow.com/questions/19104014/add-an-actionlistener-to-a-jbutton-from-another-class
public void setNewGameButtonListener(ActionListener listener){
newGameButton.addActionListener(listener);
}
public void setQuitButtonListener(ActionListener listener){
quitButton.addActionListener(listener);
}
}
还有 GameViewPanel 类。也在进行中,但像上一个类一样,这看起来应该很好。
package teekkariloikka.gui;
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import javax.swing.border.*;
public class GameViewPanel extends JPanel{
private static final long serialVersionUID = 1L;
private JButton lopetaButton;
private JButton tallennaButton;
private JButton menuButton;
BorderLayout bordL = new BorderLayout();
public GameViewPanel(){
JPanel gameViewPanel = new JPanel();
gameViewPanel.setLayout(bordL);
gameViewPanel.setBorder(new EmptyBorder(10, 10, 10, 10));
//Creating toolbar
JToolBar toolbar = new JToolBar();
toolbar.setFloatable(false);
gameViewPanel.setLayout(bordL);
gameViewPanel.setBorder(new EmptyBorder(10, 10, 10, 10));
gameViewPanel.add(toolbar, BorderLayout.PAGE_START);
//Buttons
lopetaButton = new JButton("Lopeta");
menuButton = new JButton("Päävalikko");
tallennaButton = new JButton("Tallenna");
//Adding buttons to game view toolbar
toolbar.add(lopetaButton); //TODO Add functionality!
toolbar.add(tallennaButton); //TODO Add functionality!
toolbar.add(menuButton); //TODO Add functionality!
}
public void setMainMenuButtonListener(ActionListener listener){
menuButton.addActionListener(listener);
}
}
我希望有人能指出我所犯的错误 - 无论我感觉多么愚蠢。
此外,任何其他反馈都将受到高度赞赏。正如我所说,这是我第一次编写 GUI,我必须说我时不时感到很失落。
最佳答案
cardL.show(basePanel, "2");
面板的名称不是“2”。
您定义变量MAINMENU
和GAME
来表示每个面板的名称。
关于java - CardLayout,来自单独类的面板未显示,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29087190/