我有以下 XML,其中有某些节点。我必须获取状态节点的值。由于状态节点发生多次,我必须检查它发生了多少次并按节点顺序获取值。
> <?xml version="1.0" encoding="UTF-8"?>
> <Country>
> <name>India</name>
> <capital>New Delhi</capital>
> <population>120crores</population>
> .
> .
> .
> .
> .
>
> <states>
> <state>
> <name>Maharastra</name>
> <pincode>xyzzzz</pincode>
> <capital>Mumbai</capital>
>
> <\state>
>
> <state>
> .
> .
> .
> </state>
> </states>
>
>
> <\Country>
我有以下代码部分,我将在其中检查节点长度,但我不知道如何迭代它。
> DocumentBuilderFactory dof=DocumentBuilderFactory.newInstance();
> DocumentBuilder db=dof.newDocumentBuilder();
> org.w3c.dom.Document doc=db.parse(new InputSource(new StringReader(statestring)));
> node=doc.getElementsByTagName("state");
{
int size=node.getLength();
for(int i=0;i<size;i++)
{
//how to put the logic here
}
}
最佳答案
试试这个:
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
import org.w3c.dom.Node;
import org.w3c.dom.Element;
import java.io.File;
public class ReadXMLFile {
public static void main(String argv[]) {
try {
File fXmlFile = new File("c://input.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
doc.getDocumentElement().normalize();
System.out.println("Root element :" + doc.getDocumentElement().getNodeName());
NodeList nList = doc.getElementsByTagName("state");
System.out.println("----------------------------");
for (int temp = 0; temp < nList.getLength(); temp++) {
Node nNode = nList.item(temp);
System.out.println("\nCurrent Element :" + nNode.getNodeName());
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
System.out.println("Name : " + eElement.getElementsByTagName("name").item(0).getTextContent());
System.out.println("pincode : " + eElement.getElementsByTagName("pincode").item(0).getTextContent());
System.out.println("capital : " + eElement.getElementsByTagName("capital").item(0).getTextContent());
}
}
} catch (Exception e) {
e.printStackTrace();
}
}
}
关于java - 如何仅迭代该节点并获取值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29300267/