java - 无法显示循环中的所有字符

Question

我写了一个简单的密码(不应该很难)，通过将字符更改为 char 并将索引添加到 chek 来对值进行加扰，从而对给定的字符串进行加密。问题是，当我破译代码时，它会剪切最后一个字符。现在我确信这是一个简单的菜鸟错误，但我正在努力寻找罪魁祸首。

任何帮助将不胜感激!

public class Cipher {

    public void cipher(String strArg) {
        String placeholder = strArg;

        System.out.println("Unciphered text: "+placeholder);

        char[] charArg = placeholder.toCharArray();

        char[] cipheredArg;     
        int lengthArg = charArg.length-1;       
        cipheredArg = new char[lengthArg];

        System.out.print("Ciphered text: ");

        for (int i = 0; i < lengthArg; i++) {
            char current = charArg[i];
            cipheredArg[i] = (char) (current + i);
            System.out.print(cipheredArg[i]);
        }

        System.out.print("\nDeciphered text: ");

        for (int i = 0; i < lengthArg; i++) {
            char current = cipheredArg[i];
            charArg[i] = (char) (current - i);
            System.out.print(charArg[i]);
        }
    }

    public static void main(String[] args) {
        Cipher show = new Cipher();
        show.cipher("The quick brown fox jumps over the lazy dog.");
    }
}

输出为:

Unciphered text: The quick brown fox jumps over the lazy dog.
Ciphered text: Tig#uzojs)l}{?|/v??3~????9????>???B????G???
Deciphered text: The quick brown fox jumps over the lazy dog

正如您所看到的，破译的文本中缺少点。有什么想法吗？

Answer 1

您正在对 Java 中从零开始的索引进行双重补偿

这将迭代的长度减少了 1

int lengthArg = charArg.length-1;       

这也是由于 < 运算符造成的

for (int i = 0; i < lengthArg; i++) {

规范的修复方法是使用数组的完整长度和 < 运算符

int lengthArg = charArg.length;       
// ...
for (int i = 0; i < lengthArg; i++) {