我正在开发 Android 应用程序,我在其中获取网络服务数据:
"[{\"ID\":51,\"Text\":\"!! SAMPLE PROJECT !!\"},{\"ID\":58,\"Text\":\"01 Contracting Test Project\"},{\"ID\":64,\"Text\":\"1212\"},{\"ID\":45,\"Text\":\"CHEMICAL FACTORY PROJECT\"}]"
现在我想解析json中的数据,我使用replaceAll()函数来替换字符串中的反斜杠,如下所示:
String jsonFormattedString = line.replaceAll("\\\\", "");
但我认为这个方法不好用,因为它删除了字符串中的所有反斜杠,这会产生像我收到 json 节点这样的问题:
"[{\"ID\":9617,\"Text\":\"1 1\/4\\\" PVC\/GI CLAMPS\"}]"
其中 Text 的字符串值在字符串中包含双引号,这给我带来了问题。所以我的问题是在java中解析这个json数据的最佳方法是什么。
我的webservice返回的完整json数据如下:
"[{\"ID\":51,\"Text\":\"!! SAMPLE PROJECT !!\"},{\"ID\":58,\"Text\":\"01 Contracting Test Project\"},{\"ID\":64,\"Text\":\"1212\"},{\"ID\":45,\"Text\":\"CHEMICAL FACTORY PROJECT\"},{\"ID\":53,\"Text\":\"Kanix City\"},{\"ID\":54,\"Text\":\"KANIX DREAM CITY\"},{\"ID\":59,\"Text\":\"KANIX DREAM CITY -- PHASE II\"},{\"ID\":62,\"Text\":\"KANIX DREAM CITY PHASE I\"},{\"ID\":55,\"Text\":\"Kishor_TEST\"},{\"ID\":63,\"Text\":\"Next Generation Housing\"},{\"ID\":65,\"Text\":\"Nothing Job\"},{\"ID\":56,\"Text\":\"PAVAN_TEST\"},{\"ID\":46,\"Text\":\"PRODUCTION UNITS\"},{\"ID\":1,\"Text\":\"PROJECT-01(TYPE 1)\"},{\"ID\":3,\"Text\":\"PROJECT-02(TYPE 1)\"},{\"ID\":5,\"Text\":\"PROJECT-03(TYPE 1)\"},{\"ID\":6,\"Text\":\"PROJECT-04(TYPE 1)\"},{\"ID\":7,\"Text\":\"PROJECT-05(TYPE 1)\"},{\"ID\":8,\"Text\":\"PROJECT-06(TYPE 1)\"},{\"ID\":2,\"Text\":\"PROJECT-07(TYPE 2)\"},{\"ID\":4,\"Text\":\"PROJECT-08(TYPE 2)\"},{\"ID\":9,\"Text\":\"PROJECT-09(TYPE 3)\"},{\"ID\":10,\"Text\":\"PROJECT-10(TYPE 3)\"},{\"ID\":11,\"Text\":\"PROJECT-11(TYPE 4)\"},{\"ID\":57,\"Text\":\"Reviera Classic\"},{\"ID\":43,\"Text\":\"ROAD PROJECT\"},{\"ID\":41,\"Text\":\"SAMPLE PROJECT 1\"},{\"ID\":42,\"Text\":\"SAMPLE PROJECT 2\"},{\"ID\":52,\"Text\":\"Shailesh Test project@1000\"},{\"ID\":61,\"Text\":\"VISHAL PARADISE\"},{\"ID\":60,\"Text\":\"WTC\"}]"
我的完整代码是这样的:
@Override
protected List<CItem> doInBackground(String... params) {
try {
String line="";
String ur = "http://"+ServerDetails.hostServer+"/appservices.svc/Projects?Keyword=" ;
lstItm=new ArrayList<CItem>() ;
// Replace it with your own WCF service path
URL json = new URL(ur);
URLConnection jc = json.openConnection();
BufferedReader reader = new BufferedReader(new InputStreamReader(jc.getInputStream()));
line = reader.readLine();
Log.d("LINE",line);
JSONArray array=new JSONArray(line);
Itm=new CItem( "-1", "Select Project" );
lstItm.add(Itm);
for(int i=0; i < array.length(); i++) {
JSONObject tmpJson=array.getJSONObject(i);
Itm=new CItem(tmpJson.getString("ID"),tmpJson.getString("Text"));
lstItm.add(Itm);
}
return lstItm ;
}
catch(Exception e)
{
Log.d("ERRROR--->",e.getMessage());
}
return lstItm ;
}
最佳答案
@mubu9082 ..你不需要删除这些反斜杠... 因为这个 json 字符串在日志中或调试器中显示为带有反斜杠..
照常解析即可
public void jsonParser()
{
ArrayList<> list=new ArrayList<>(); //declare this as global
String responseString="[{\"ID\":51,\"Text\":\"!! SAMPLE PROJECT !!\"},{\"ID\":58,\"Text\":\"01 Contracting Test Project\"},{\"ID\":64,\"Text\":\"1212\"},{\"ID\":45,\"Text\":\"CHEMICAL FACTORY PROJECT\"}]";
JSONArray array=new JSONArray(responseString);
String id[]=new String[array.length()];
String text[]=new String[array.length()];
for(int i=0;i<array.length();i++)
{
JSONObject tmpJson=array.getJSONObject(i);
id[i]=tmpJson.getString("ID");
text[i]=tmpJson.getString("TEXT");
CItem Itm=new CItem(tmpJson.getString("ID"),tmpJson.getString("Text")); lstItm.add(Itm);
list.add(Itm);
}
}
这样做是为了从服务器获取响应
try {
// create HttpClient
HttpClient httpclient = new DefaultHttpClient();
// make GET request to the given URL ...use
HttpResponse httpResponse = httpclient.execute(new HttpGet(url));
// receive response as inputStream
HttpEntity entity = httpResponse.getEntity();
String response= EntityUtils.toString(entity);
//pass this response to JSONArray object
//save response and then flush the entity.
entity.consumeContent();
} catch (Exception e) {
Log.d("InputStream", e.getLocalizedMessage());
}
将此响应传递给 JSONArray 对象
关于java - 在java中解析来自webservice的json数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30252445/