Android，通过 HTTP POST 方法发送和接收 XML

Question

有一个相关的问题，但我无法清楚地得到答案。

我想发布一个简短的 xml 代码

<aaaLogin inName="admin" inPassword="admin123"/>

通过 HTTP 发送到特定的 URL 地址。 Web 服务将向我发回一个 XML 代码。重要的部分是我将解析接收到的 XML，并且我想将其存储为一个文件。

    // Create a new HttpClient and Post Header  
    HttpClient httpclient = new DefaultHttpClient();  
    HttpPost httppost = new HttpPost("http://192.168.192.131/"); //URL address

    StringEntity se = new StringEntity("<aaaLogin inName=\"admin\" inPassword=\"admin123\"/>",HTTP.UTF_8); //XML as a string
    se.setContentType("text/xml"); //declare it as XML
    httppost.setHeader("Content-Type","application/soap+xml;charset=UTF-8");
    httppost.setEntity(se);

    BasicHttpResponse httpResponse = (BasicHttpResponse) httpclient .execute(httppost);
    tvData.setText(httpResponse.getStatusLine().toString()); //text view is expected to print the response

接收响应有问题。此外，我没有写任何东西来将收到的 XML 保存为文件。有人可以写一段代码吗？

Answer 1

好的，我发布这个问题后很快就想通了。 这段代码在这里工作正常:

HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://192.168.192.131/");

try {
    StringEntity se = new StringEntity( "<aaaLogin inName=\"admin\" inPassword=\"admin123\"/>", HTTP.UTF_8);
    se.setContentType("text/xml");
    httppost.setEntity(se);

    HttpResponse httpresponse = httpclient.execute(httppost);
    HttpEntity resEntity = httpresponse.getEntity();
    tvData.setText(EntityUtils.toString(resEntity));        
} catch (ClientProtocolException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
} catch (IOException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}