具有文件名数组的 Java InputData 读/写循环

Question

这里对 java 非常非常陌生。目前，我有代码从单个文本文件中提取数据，并以我可用的格式解析数据(见下文)。不幸的是，这要求我必须更改每次运行的文件名。理想情况下，我希望通过循环文件名字符串数组来收集数据来自动化它。

知道如何传递文件名数组并循环遍历每个名​​称吗？

package weatherfiledata;


import java.io.*;

/**
 *
 *
 */
public class WeatherFileData {
    int month[] = new int[8760];
    int day[] = new int[8760];
    int hour[] = new int[8760];
    int db[] = new int[8760];
    int wb[] = new int[8760];
    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        int count;
        //here i would declare the array of fileNames and start the loop
        //String fileNames[] = {"fileName1","fileName2"...};
        //for(count = 0; count < fileNames.length; count++){


        // TODO code application logic here
        //create an object named "DataInput" of type "WeatherFileData"
        WeatherFileData DataInput = new WeatherFileData();

        DataInput.InputData(DataInput);
        //display data
        int i;
        for(i=0; i<DataInput.month.length; i++) {
            System.out.print(DataInput.wb[i] +",");
        }
        //} end of loop
    }

        void InputData(WeatherFileData DataInput) {
         BufferedReader br = null;
         try {

        String sCurrentLine;
        //this is where I currently have to change the fileName each time;
        //I would like to be able to use the fileName array loop to automate
        br = new BufferedReader(new FileReader("fileName1.txt"));

        int i=0;
        while ((sCurrentLine = br.readLine()) != null) {
            String arr[] = sCurrentLine.split("\t");

            DataInput.month[i] = Integer.parseInt(arr[0]);
            DataInput.day[i] = Integer.parseInt(arr[1]);
            DataInput.hour[i] = Integer.parseInt(arr[2]);
            DataInput.wb[i] = Integer.parseInt(arr[3]);
            DataInput.db[i] = Integer.parseInt(arr[4]);
            i++;
        }

    } catch (IOException e) {
        e.printStackTrace();
    } finally {
        try {
            if (br != null)br.close();
        } catch (IOException ex) {
            ex.printStackTrace();
        }
    }
    }

}

Answer 1

您应该首先为文件名引入一个字符串变量:

br = new BufferedReader(new FileReader(filename));

并将此变量作为参数传递给您的方法:

void inputData(WeatherFileData dataInput, String filename) {

然后，您可以在数组中维护这些文件的列表:

String[] filenames = new String[5];
filenames[0] = "fileName1.txt";
...

并通过以下方式迭代它们:

for(String filename : filenames){
   WeatherFileData dataInput = new WeatherFileData();
   dataInput.inputData(dataInput, filename);
   ... // Do what you want with DataInput
}

作为最后一条评论，请注意您不需要这样做:

dataInput.inputData(dataInput, filename);

这样会更好:

dataInput.inputData(filename);

但在函数 inputData() 中写下:

this.month[i] = Integer.parseInt(arr[0]);

而不是这个:

dataInput.month[i] = Integer.parseInt(arr[0]);

(我还删除了对象和方法名称中的大写首字母，这是惯例)