java - 我的智囊游戏中的 For 循环

Question

我试图在我的游戏中创建一个 for 循环，以便当猜测的数量相加时，它会进入 for 循环并给出正确猜测的数量。这是我的计算机科学课的内容，我们必须将 for 循环合并到程序中。

if (guess1 == Secret_code[0]) {
    System.out.println(" You have guessed one correctly in the right spot!");
}

if (guess2 == Secret_code[1]) {
    System.out.println(" You have guessed one correctly in the right spot!");
}

if (guess3 == Secret_code[2]) {
    System.out.println(" You have guessed one correctly in the right spot!");
}

if (guess4 == Secret_code[3]) {
    System.out.println(" You have guessed one correctly in the right spot!");
}

do {
    System.out.println("What is the number one peg in my code???");
    guess1 = Guess.nextInt();
    System.out.println("What is the number two peg in my code???");
    guess2 = Guess.nextInt();
    System.out.println("What is the number three peg in my code???");
    guess3 = Guess.nextInt();
    System.out.println("What is the number four peg in my code???");
    guess4 = Guess.nextInt();
    if (guess1 == Secret_code[0]) {
        System.out.println(" You have guessed one correctly in the right spot!");
    }
    if (guess2 == Secret_code[1]) {
        System.out.println(" You have guessed one correctly in the right spot!");
    }
    if (guess3 == Secret_code[2]) {
        System.out.println(" You have guessed one correctly in the right spot!");
    }
    if (guess4 == Secret_code[3]) {
        System.out.println(" You have guessed one correctly in the right spot!");
    }
}
while ((guess1 != Secret_code[0]) & (guess2 != Secret_code[1]) & (guess3 != Secret_code[2]) & (guess4 != Secret_code[3]));    

public static void CorrectGuess(int[] Secret_code) {
    //Variables
    int Correctspot;

    for (Secret_code[0] = 0; Secret_code[0] < 3; Secret_code[0]++)
        Correctspot = +1;
}

Answer 1

我只会向您展示一个示例，因为就像他们说的那样，这不是我们的工作，但我感觉很糟糕，因为他们是一些糟糕的老师。我还会构建一个数组，因为这将解决您可能遇到的所有问题

//make a Scanner obj
Int[] guessArray = {10, 20, 30, 5};    
int useranswer = 0;
int loopCount = 0;

while(loopCount < 4) {
    System.out.println("blalalala for Guess #" + (loopCount+1));
    useranswer = input.nextInt();

    if(useranswer == guessArray[loopCount]) {
        loopCount++;
    }//end of if

}//end of while loop

拥有一个数组列表将有助于保持一切有序，并且您可以在程序稍后的循环之后放弃这些值。您始终需要小心 while 循环，因为如果代码错误，您最终可能会导致计算机崩溃。

我还会查找 for 循环，因为根据您 future 的问题，for 或 while 可能效果最好。

致编辑编码风格的人[1]: 注意:我通过将所有内容分开进行编码，因为它可以帮助我看到所有内容，如果这是一个问题，请告诉我。这样我就可以事后更改它