该程序应该将二进制数转换为十进制数,并在输入有非二进制数时抛出异常。这个程序会读取1,但是当我输入0时,它会抛出异常并告诉我它不是二进制。
测试程序:
//Prepare scanner from utility for input.
import java.util.Scanner;
public class Bin2Dec {
public static void main (String[] args){
//Convert the input string to their decimal equivalent.
//Open scanner for input.
Scanner input = new Scanner(System.in);
//Declare variable s.
String s;
//Prompt user to enter binary string of 0s and 1s.
System.out.print("Enter a binary string of 0s and 1s: ");
//Save input to s variable.
s = input.nextLine();
//With the input, use try-catch blocks.
//Print statement if input is valid with the conversion.
try {
System.out.println("The decimal value of the binary number "+ "'" + s + "'" +" is "+conversion(s));
//Catch the exception if input is invalid.
} catch (BinaryFormatException e) {
//If invalid, print the error message from BinaryFormatException.
System.out.println(e.getMessage());
}
}
//Declare exception.
public static int conversion(String parameter) throws BinaryFormatException {
int digit = 0;
for (int i = parameter.length(); i > 0; i--) {
char wrong_number = parameter.charAt(i - 1);
if (wrong_number == '1') digit += Math.pow(2, parameter.length() - i);
//Make an else statement and throw an exception.
else
throw new BinaryFormatException("");
}
return digit;
}
}
异常程序:
public class BinaryFormatException extends Exception {
//Declare message.
private String message;
public BinaryFormatException(String msg) {
this.message = msg;
}
//Return this message for invalid input to Bin2Dec class.
public String getMessage() {
return "Error: This is not a binary number";
}
}
最佳答案
如果 char 不是 1,则抛出 BinaryFormatException 异常。
if (wrong_number == '1') digit += Math.pow(2, parameter.length() - i);
//Make an else statement and throw an exception.
else
throw new BinaryFormatException("");
关于java - 为什么我的二进制到十进制转换程序读不到 0?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32783890/