Java:迭代并获取每n个项目

Question

我尝试迭代一组数字，每完成 6 个项目后，我就需要进行一次剪切。以下是示例代码:

int c = 1;
StringBuffer sb = new StringBuffer();
for(int x = 1; x < 32; x++) {
    sb.append(x+ ",");
    c++;
    if (c == 6) {
        System.out.println("ADDED TO COLLECTION: " + sb.toString());
        sb = new StringBuffer();
        c = 0;
    }
}

输出:

ADDED TO COLLECTION: 1,2,3,4,5,
ADDED TO COLLECTION: 6,7,8,9,10,11,
ADDED TO COLLECTION: 12,13,14,15,16,17,
ADDED TO COLLECTION: 18,19,20,21,22,23,
ADDED TO COLLECTION: 24,25,26,27,28,29,

缺少 Nr。 31 - 如何实现？

Answer 1

您可以在末尾添加 println:

    int c = 1;
    StringBuffer sb = new StringBuffer();
    for (int x = 1; x < 32; x++) {
        sb.append(x + ",");
        c++;
        if (c == 6) {
            System.out.println("ADDED TO COLLECTION: " + sb.toString());
            sb = new StringBuffer();
            c = 0;
        }
    }
    // after the last iteration there is still something left in sb:
    System.out.println("ADDED TO COLLECTION: " + sb.toString());

您还可以添加检查 sb 中是否确实存在某些内容并跳过打印。