这是我到目前为止编写的代码。我的游戏工作得很好，但我遇到的问题是，如果用户输入一个已经占据的位置，是的，它会不断要求用户输入，但我希望它做什么:这个位置不可用，然后重新询问用户直到好为止。我想过一个 for 循环，但是对于我的循环，它说它不可用，即使它不是......我已经研究这个好几天了。如果有人能给我一些提示，我将不胜感激。
import java.util.Scanner;
public class A3Q1_40011419 {
//Creating the board for the user input
static char [][] board = {{'1','2','3'}, {'4','5','6'},{'7','8','9'}};
static Scanner keyboard = new Scanner (System.in);
//Keeping track of the turns
public static int turns = 0;
//Drawing the board
public static void drawBoard() {
int row = 0;
int col = 0;
int turn = 0;
for (row = 0; row < board.length; row++){
for (col = 0; col < board[row].length; col++){
System.out.print(board[row][col]);
System.out.print(" ");
}
System.out.println();
}
}
//Asking user for input
public static void getInput (int playerNum) {
char piece;
char location = ' ';
if (playerNum != 1){
System.out.println("Player X - Enter the position you wish to mark.");
location = keyboard.next().charAt(0);
piece = 'X';
}
else{
System.out.println("Player O - Enter the position you wish to mark.");
location = keyboard.next().charAt(0);
piece = 'O';
}
if (location == '1')
if (board[0][0]=='1')
board[0][0] = piece;
else getInput(playerNum);
else if (location == '2')
if (board[0][1] == '2')
board[0][1] = piece;
else getInput(playerNum);
else if (location == '3')
if (board[0][2] == '3')
board[0][2] = piece;
else getInput(playerNum);
else if (location == '4')
if (board[1][0] == '4')
board[1][0] = piece;
else getInput(playerNum);
else if (location == '5')
if (board[1][1] == '5')
board[1][1] = piece;
else getInput(playerNum);
else if (location == '6')
if (board[1][2] == '6')
board[1][2] = piece;
else getInput(playerNum);
else if (location == '7')
if (board[2][0] == '7')
board[2][0] = piece;
else getInput(playerNum);
else if (location == '8')
if (board[2][1] == '8')
board[2][1] = piece;
else getInput(playerNum);
else if (location == '9')
if (board[2][2] == '9')
board[2][2] = piece;
else getInput(playerNum);
else if (location != '1' || location !='2' || location !='3' || location != '4' || location !='5' || location !='6' || location != '7' || location != '8'|| location !='9'){
System.out.println("That is not a valid position - must be between 1 and 9 inclusive.");
getInput(playerNum);
}
for (int i = 0; i<board.length; i++){
for (int j = 0; j<board.length; j++)
/*if (location == '1' || location == '2' || location == '3'|| location == '4' || location == '5'|| location == '6' || location == '7' || location == '8' || location == '9')*/
if (board[i][j] == 'X' || board[i][j] == 'O'){
System.out.println("Position not available"); //This is was i tried to do so far to check is the position was available on the board. Not working
}
getInput(playerNum);
}
}
//Checking if position available
public static void isAvailable(){ //This is a method i thought of creating to check if the position was available but I have not used it yet.
char location_1 = ' ';
char location_2 = ' ';
char location_3 = ' ';
char location_4 = ' ';
char location_5 = ' ';
char location_6 = ' ';
char location_7 = ' ';
char location_8 = ' ';
char location_9 = ' ';
}
/*Checking if there is a winner by checking if the cells in the board are equal to each other
*and checking if the cell isn't empty. If one isn't empty and they're all equal, then
none of them is empty.*/
public static char isWinner() {
if (board[0][0] == board[1][1] && board[0][0] == board[2][2] && board[0][0]!='1')
return board[0][0];
else if (board[0][0] == board[1][0] && board[0][0] == board[2][0] && board[0][0]!='1')
return board[0][0];
else if (board[0][0]==board[0][1] && board[0][0]==board[0][2] && board[0][0]!='1')
return board[0][0];
else if (board[0][2] == board[1][1] && board[0][2] == board[2][0] && board[0][2] !='3')
return board[0][2];
else if (board[0][2] == board[1][2] && board[0][2] == board[2][2] && board[0][2] != '3')
return board[0][2];
else if (board[2][0] == board [2][1] && board[2][0] == board[2][2] && board[2][0] != '7')
return board[2][0];
else if (board[1][0] == board [1][1] && board[1][0] == board[1][2] && board[1][0] != '4')
return board[1][0];
else if (board[0][1] == board[1][1] && board[0][1] == board[2][1] && board[0][1] != '2')
return board[0][1];
else
return 'Y';
}
//New board for a new game
public static void newBoard() {
board[0][0] = '1';
board[0][1] = '2';
board[0][2] = '3';
board[1][0] = '4';
board[1][1] = '5';
board[1][2] = '6';
board[2][0] = '7';
board[2][1] = '8';
board[2][2] = '9';
}
//Main method
public static void main(String[] args) {
int game = 0;
int playerNum = 1;
String answer;
do {
turns = 0;
newBoard();
while (isWinner() == 'Y') {
drawBoard();
isWinner();
playerNum *= -1;
getInput(playerNum);
turns++;
System.out.println(turns);
if (turns == 9) {
break;
}
}
drawBoard();
if (isWinner() == 'X')
System.out.println("Player X wins");
else if (isWinner()=='O')
System.out.println("Player O wins");
else
System.out.println("It's a tie!");
System.out.println("Would you like to play another game?");
answer = keyboard.next().toLowerCase();
}
while (answer.equals("yes"));
}
}
最佳答案
我建议:
在插入新输入之前，您将检查移动到可用位置。
您只需检查玩家询问的位置，而不是循环检查网格的所有位置。
请在下面找到有效的代码:
public class A3Q1_40011419 {
//Creating the board for the user input
static char [][] board = {{'1','2','3'}, {'4','5','6'},{'7','8','9'}};
static Scanner keyboard = new Scanner (System.in);
//Keeping track of the turns
public static int turns = 0;
//Drawing the board
public static void drawBoard() {
int row = 0;
int col = 0;
int turn = 0;
for (row = 0; row < board.length; row++){
for (col = 0; col < board[row].length; col++){
System.out.print(board[row][col]);
System.out.print(" ");
}
System.out.println();
}
}
//Asking user for input
public static void getInput (int playerNum) {
char piece;
char location = ' ';
if (playerNum != 1){
System.out.println("Player X - Enter the position you wish to mark.");
location = keyboard.next().charAt(0);
piece = 'X';
}
else{
System.out.println("Player O - Enter the position you wish to mark.");
location = keyboard.next().charAt(0);
piece = 'O';
}
//------------------------
// Your new check
int locationInt = Integer.parseInt("" + location);
int x = (locationInt-1)/3;
int y = ((locationInt-1)%3);
if (board[x][y] == 'X' || board[x][y] == 'O'){
System.out.println("Position not available"); //This is was i tried to do so far to check is the position was available on the board. Not working
getInput(playerNum);
return;
}
//------------------------
if (location == '1')
if (board[0][0]=='1')
board[0][0] = piece;
else getInput(playerNum);
else if (location == '2')
if (board[0][1] == '2')
board[0][1] = piece;
else getInput(playerNum);
else if (location == '3')
if (board[0][2] == '3')
board[0][2] = piece;
else getInput(playerNum);
else if (location == '4')
if (board[1][0] == '4')
board[1][0] = piece;
else getInput(playerNum);
else if (location == '5')
if (board[1][1] == '5')
board[1][1] = piece;
else getInput(playerNum);
else if (location == '6')
if (board[1][2] == '6')
board[1][2] = piece;
else getInput(playerNum);
else if (location == '7')
if (board[2][0] == '7')
board[2][0] = piece;
else getInput(playerNum);
else if (location == '8')
if (board[2][1] == '8')
board[2][1] = piece;
else getInput(playerNum);
else if (location == '9')
if (board[2][2] == '9')
board[2][2] = piece;
else getInput(playerNum);
else if (location != '1' || location !='2' || location !='3' || location != '4' || location !='5' || location !='6' || location != '7' || location != '8'|| location !='9'){
System.out.println("That is not a valid position - must be between 1 and 9 inclusive.");
getInput(playerNum);
}
}
//Checking if position available
public static void isAvailable(){ //This is a method i thought of creating to check if the position was available but I have not used it yet.
char location_1 = ' ';
char location_2 = ' ';
char location_3 = ' ';
char location_4 = ' ';
char location_5 = ' ';
char location_6 = ' ';
char location_7 = ' ';
char location_8 = ' ';
char location_9 = ' ';
}
/*Checking if there is a winner by checking if the cells in the board are equal to each other
*and checking if the cell isn't empty. If one isn't empty and they're all equal, then
none of them is empty.*/
public static char isWinner() {
if (board[0][0] == board[1][1] && board[0][0] == board[2][2] && board[0][0]!='1')
return board[0][0];
else if (board[0][0] == board[1][0] && board[0][0] == board[2][0] && board[0][0]!='1')
return board[0][0];
else if (board[0][0]==board[0][1] && board[0][0]==board[0][2] && board[0][0]!='1')
return board[0][0];
else if (board[0][2] == board[1][1] && board[0][2] == board[2][0] && board[0][2] !='3')
return board[0][2];
else if (board[0][2] == board[1][2] && board[0][2] == board[2][2] && board[0][2] != '3')
return board[0][2];
else if (board[2][0] == board [2][1] && board[2][0] == board[2][2] && board[2][0] != '7')
return board[2][0];
else if (board[1][0] == board [1][1] && board[1][0] == board[1][2] && board[1][0] != '4')
return board[1][0];
else if (board[0][1] == board[1][1] && board[0][1] == board[2][1] && board[0][1] != '2')
return board[0][1];
else
return 'Y';
}
//New board for a new game
public static void newBoard() {
board[0][0] = '1';
board[0][1] = '2';
board[0][2] = '3';
board[1][0] = '4';
board[1][1] = '5';
board[1][2] = '6';
board[2][0] = '7';
board[2][1] = '8';
board[2][2] = '9';
}
//Main method
public static void main(String[] args) {
int game = 0;
int playerNum = 1;
String answer;
do {
turns = 0;
newBoard();
while (isWinner() == 'Y') {
drawBoard();
isWinner();
playerNum *= -1;
getInput(playerNum);
turns++;
System.out.println(turns);
if (turns == 9) {
break;
}
}
drawBoard();
if (isWinner() == 'X')
System.out.println("Player X wins");
else if (isWinner()=='O')
System.out.println("Player O wins");
else
System.out.println("It's a tie!");
System.out.println("Would you like to play another game?");
answer = keyboard.next().toLowerCase();
}
while (answer.equals("yes"));
}
}
关于java - 井字游戏 java : what to do if the user inputs a position that's already taken?，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/33465587/