这是代码
protected Void doInBackground(String... params) {
String reg_url = "http://10.0.2.2/";
String method = params [0];
if (method.equals("register") ){
String first_name = params [1];
String last_name = params [2];
String address = params [3];
String email = params [4];
String password = params [5];
try {
URL url = new URL(reg_url);
HttpURLConnection httpURLConnection = (HttpURLConnection)url.openConnection();
HttpURLConnection.setRequestMethod("POST");
HttpURLConnection.setDoOutput(True);
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
return null;
}
我在这两行上收到错误
HttpURLConnection.setRequestMethod("POST");
HttpURLConnection.setDoOutput(True);
关于 set.RequestMethod("POST") 和 "setDoOutput(true); 错误表示无法从静态上下文引用非静态方法。 这一定是一个愚蠢的错误,但我就是无法弄清楚,所以有人可以帮我解决这个问题吗?
最佳答案
使用您在调用 openConnection
中获得的实例:
HttpURLConnection httpURLConnection = (HttpURLConnection)url.openConnection();
httpURLConnection.setRequestMethod("POST");
httpURLConnection.setDoOutput(true);
请注意,Java 区分大小写。 HttpURLConnection
是类名。 httpURLConnection
是一个引用该类实例的变量。
关于java - 如何解决此错误,无法从静态上下文引用非静态方法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34250756/