java - Hibernate 返回 util.Date as long

Question

我有日期为 util.Date 的域类。当我运行 jpa 方法时，从数据库中查找行。它返回长日期而不是实际日期。有人可以帮忙吗？

编辑:

域名:

import java.util.Date;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;

import org.hibernate.annotations.Formula;

@Entity
public class Expense {
    @Id
    @GeneratedValue(strategy=GenerationType.IDENTITY)
    int intTranId;

    BigDecimal fltAmt;
    Date dtDate;
    ....
    /setter getter methods

存储库:

import java.util.Date;
import org.springframework.data.jpa.repository.Query;
import org.springframework.data.repository.CrudRepository;
import org.springframework.stereotype.Repository;

import com.ext.domain.Expense;
@Repository
public interface ExpenseRepository extends CrudRepository<Expense, Integer>{
    @Query("SELECT min(dtDate) as dtDate ,Max(dtDate) as dtDate FROM Expense")
    Iterable<Date> getAvlRptDates();

    @Query("SELECT monthYear FROM Expense group by Year(dtDate),Month(dtDate) order by Year(dtDate),Month(dtDate)")
    Iterable<String> getAvlRptRecords();


    Iterable<Expense> findAll();
}

findAll 返回的值为

[{"intTranId":1064,"fltAmt":2.00,"dtDate":1454481056294,"monthYear":"2016-1","category":{"intCatId":5,"strCatName":"Grocery"}}]

Answer 1

@Column(name = "DatabaseColumnName")
@DateTimeFormat(pattern = "YYYY-MM-DD")
@Temporal(TemporalType.DATE)
private Date dtDate;

请使用 DateTimeFormat 将数据库日期与费用类实体映射