Java扫描器对象跳行？

Question

自从我真正为 java 编写任何基于控制台的东西以来已经有一段时间了，

我有下面这个方法，它应该询问我每一行，对吧？相反，我收到一个提示，然后是三个提示。我在这里做错了什么？

        try {

        System.out.println("Please enter the product's LONG details: ");
        product.setLongDetails(sc.next()); //set products long details

        System.out.println("Please enter the product's SHORT details: ");
        product.setShortDetails(sc.next()); //set short details

        System.out.println("Please enter the product's UPC data: ");
        product.setUpc(sc.next()); //set upc

        System.out.println("Please enter the product's stock: ");
        product.setStock(sc.nextInt());

        System.out.println("Please enter the products price. ");
        System.out.println("This MUST be entered with no dollar sign.");
        product.setPrice(sc.nextBigDecimal());

        InventoryManager.addProduct(product); //add product to database

    }

我的控制台输出如下:

Please enter the product's LONG details: 
Fireplace Cleaning Package
Please enter the product's SHORT details: 
Please enter the product's UPC data: 
Please enter the product's stock: 
BUILD STOPPED (total time: 3 minutes 5 seconds)

扫描仪在类声明中初始化为:

public static Scanner sc = new Scanner(System.in); //class level scanner object for reuse.

如果我在每个对象设置方法之间调用 sc.nextLine()，它会正确提示但获取错误信息:

Please enter the product's SHORT details: 
Fire Poker

将对象显示为: 请输入您的选择: 火

Answer 1

documentation状态:

A Scanner breaks its input into tokens using a delimiter pattern, which by default matches whitespace.

这意味着当您输入带有空格的文本(例如示例中的“壁炉清洁包”)时，它会分为 3 个不同的输入，每个输入均由 sc.next() 的一次调用返回.

解决方案是将分隔符模式调整为换行符:

sc.useDelimeter("\\r?\\n");