如何使用 Java 获取文本文件两行之间的文本? 我尝试这样做,但它不起作用:
String input = "!!!Error deploying file order\\POST_ORDER_UpdateTaxAmountCurrInCo.sql at 22-JUL-16 08:07:Chathura aBhanakana1!!!Error deploying file order\\POST_ORDER_";
Pattern p = Pattern.compile("(?<=\\b!!!Error deploying file\\b).*?(?=\\b!!!Error deploying file\\b)");
Matcher m = p.matcher(input);
List<String> matches = new ArrayList<String>();
while (m.find()) {
System.out.println("A " + m.group());
}
最佳答案
更新答案
使用正则表达式
String pattern = "([\\s\\S]*?)(!!!Error deploying file)";
上述模式的解释。
- *? - 匹配单个字符零次到无限次
- \s - 匹配任何空白字符
- \S - 匹配任何非空白字符
示例代码:
String line = "!!!Error deploying file order\\POST_ORDER_UpdateTaxAmountCurrInCo.sql at 22-JUL-16 08:07:Chathura aBhanakana1!!!Error deploying file order\\POST_ORDER_UpdateTaxAmountChathura aBhanakana1AAAAA !!!Error deploying file order\\POST";
String pattern = "([\\s\\S]*?)(!!!Error deploying file)";
// Create a Pattern object
Pattern r = Pattern.compile(pattern);
// Now create matcher object.
Matcher m = r.matcher(line);
while (m.find( )) {
String str = m.group(1);
if(str != null && !str.isEmpty()){
System.out.println("Found value: " + str );
}
}
输出
- 发现值:order\POST_ORDER_UpdateTaxAmountCurrInCo.sql,位于 2016 年 7 月 22 日 08:07:Chathura aBhanakana1
- 发现值: 订单\POST_ORDER_UpdateTaxAmountChathura aBhanakana1AAAAA
使用分割方法
示例代码:
String line = "!!!Error deploying file order\\POST_ORDER_UpdateTaxAmountCurrInCo.sql at 22-JUL-16 08:07:Chathura aBhanakana1!!!Error deploying file order\\POST_ORDER_UpdateTaxAmountChathura aBhanakana1AAAAA !!!Error deploying file order\\POST";
for (String retval: line.split("!!!Error deploying file")){
System.out.println(retval);
}
输出:
1 ) order\POST_ORDER_UpdateTaxAmountCurrInCo.sql at 22-JUL-16 08:07:Chathura aBhanakana1
2) order\POST_ORDER_UpdateTaxAmountChathura aBhanakana1AAAAA
3) order\POST
关于java - 如何使用java获取文本文件两行之间的文本,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38584845/