我正在尝试解析以下 json
{
"effect_list": [{
"1":[
{
"effects_id":"1",
"effects_name":"Band 1"
},
{
"effects_id":"2",
"effects_name":"Band 2"
}
],
"2": [
{
"effects_id":"4",
"effects_name":"Background Blur"
},
{
"effects_id":"5",
"effects_name":"Blemish Removal"
}
]
}]
}
我的 BaseAdapter 仅显示 ListView 中的最后一个项目。我正在尝试检索 Map 中的值。在迭代过程中,值会被覆盖。当我打印键和值时,所有值都会正确显示。它显示完整的键和值。
我在这里做错了什么?
MyContactAdapter2.java
public class MyContactAdapter2 extends BaseAdapter {
List<Map<String, List<EffectList>>> contactList;
Context context;
private LayoutInflater mInflater;
// Constructors
public MyContactAdapter2(Context context, List<Map<String, List<EffectList>>> objects) {
this.context = context;
this.mInflater = LayoutInflater.from(context);
contactList = objects;
}
public MyContactAdapter2() {
System.out.println("hai");
}
@Override
public int getCount() {
int count = contactList.size();
System.out.println("Count size" + count);
return count;
}
@Override
public Map<String, List<EffectList>> getItem(int position) {
return contactList.get(position);
}
@Override
public long getItemId(int position) {
return 0;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
System.out.println(10);
final MyContactAdapter2.ViewHolder vh;
if (convertView == null) {
View view = mInflater.inflate(R.layout.get_layout_row_view, parent, false);
vh = MyContactAdapter2.ViewHolder.create((RelativeLayout) view);
view.setTag(vh);
} else {
vh = (MyContactAdapter2.ViewHolder) convertView.getTag();
}
for (Map<String, List<EffectList>> map : contactList) {
for (Map.Entry<String, List<EffectList>> entry : map.entrySet()) {
String key = entry.getKey();
Object value = entry.getValue();
System.out.println("key :" + key + "value :" + value);
EffectList item = getItem(position).get(key).get(0);
vh.textViewName.setText(item.getEffectsId());
vh.textViewEmail.setText(item.getEffectsName());
}
}
return vh.rootView;
}
private static class ViewHolder {
public final RelativeLayout rootView;
public final ImageView imageView;
public final TextView textViewName;
public final TextView textViewEmail;
private ViewHolder(RelativeLayout rootView, ImageView imageView, TextView textViewName, TextView textViewEmail) {
this.rootView = rootView;
this.imageView = imageView;
this.textViewName = textViewName;
this.textViewEmail = textViewEmail;
}
public static MyContactAdapter2.ViewHolder create(RelativeLayout rootView) {
ImageView imageView = (ImageView) rootView.findViewById(R.id.imageView);
TextView textViewName = (TextView) rootView.findViewById(R.id.textViewName);
TextView textViewEmail = (TextView) rootView.findViewById(R.id.textViewEmail);
return new MyContactAdapter2.ViewHolder(rootView, imageView, textViewName, textViewEmail);
}
}
}
最佳答案
问题出在这部分代码:
for (Map<String, List<EffectList>> map : contactList) {
for (Map.Entry<String, List<EffectList>> entry : map.entrySet()) {
String key = entry.getKey();
Object value = entry.getValue();
System.out.println("key :" + key + "value :" + value);
EffectList item = getItem(position).get(key).get(0);
vh.textViewName.setText(item.getEffectsId());
vh.textViewEmail.setText(item.getEffectsName());
}
}
对于每个列表项,您将依次设置键和值。所以在 for 循环结束时,只剩下最后一个。
例如:联系人列表 - {you, me, dupree} 你正在做的是
- vh.textViewName(您)
- vh.textViewName(我)
- vh.textViewName(dupree)
因此您将始终在列表中看到 dupree。
<小时/>不要使用 contactList 创建 MyContactAdapter2,而是传递 Map<String, List<EffectList>> map
直接
如果您只想在列表中显示textViewName 和textViewEmail。然后创建包含姓名和电子邮件的对象列表。
class Contact {
public String name;
public String email;
}
List<Contact> contacts;
现在将此联系人传递给适配器。保持简单。
关于java - 仅 ListView 中的最后一项显示在 BaseAdapter 中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41459239/