java - 如果 switch 中默认输入会忽略 IF 语句

Question

我正在做一个项目(基于教程)。我有一个 switch 语句，对于每种情况，都有一个默认值，以防用户输入无效，我在控制台上写“抱歉，我不明白您的请求”。但是，如果用户不写任何内容，而是写“退出”，则程序应该结束，而不会出现“我不明白请求”的句子。

这在我开头的 IF 语句中已说明。当我输入“exit”时，我当前的项目所做的就是显示该行然后停止。我不明白程序如何在开始时完全忽略该 IF 语句。

public class MainGame {

public static GameSave gameSave = new GameSave();
public static String user = "";
public static Scanner scanner = new Scanner(System.in);
public static String question;
public static int relationshipPoints;

public static void main(String[] args) {
        Random random = new Random();
        question = gameSave.loadGame();
        // relationshipPoints = gameSave.loadPoints();
        RelationshipPoints points = new RelationshipPoints();

        System.out.println("\n\t*** TEXT_GAME: FIRSTDATE ***\n");
        System.out.println("-You can exit the game at any time by typing 'exit'.-\n\n");

        while (true) {

            if (user.equalsIgnoreCase("exit")) {
                System.exit(1);
                break;
            } else {
                switch (question) {
                [...]
                case "2":
                    switch (user = scanner.next()) {
                    case "1":
                        System.out.println("\n\nThe guy you met last night was nice. You want to "
                                + "get back into contact with him. Why don't you check your phone for a number?");
                        question = "2A";
                        gameSave.saveGame("2A");
                        break;
                    case "2":
                        System.out.println("\n\n");
                        question = "0";
                        break;
                    default:
                        System.out.println("\nI do not understand your request.\n");
                        question = "2";
                        break;
                    }
                    break;
                case "2A": [...]

Answer 1

尝试将 while(true) {...} 替换为 while ((user = Scanner.next() != null) { ... }

看起来您正在尝试访问“用户”数据而不先进行设置。