我正在尝试为 Java Spring 批处理应用程序、DAO 层编写 junit 测试用例。当我使用自定义序列生成器配置数据层对象并运行测试用例时,我收到以下异常。
异常描述:SEQ_EMPLOYEE_ID:平台DatabasePlatform不支持NativeSequence。
对于数据持久性,我使用 JPA+EclipseLink。
下面提到了我用于 Junit 的配置文件。
DO 类(class)
@Entity
@Table(name = "EMPLOYEE")
@NamedQuery(name = "test.test",
query = "SELECT d FROM EmployeeDO d where d.status = 'COMPLETED'")
public class EmployeeDO implements Serializable {
private static final long serialVersionUID = 1L;
@SequenceGenerator(name = "employeeIdSequence", allocationSize = 1,
sequenceName = "SEQ_EMPLOYEE_ID")
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "employeeIdSequence")
@Column(name = "BATCH_ID")
private long batchId;
}
JunitPersistence.xml
persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0">
<persistence-unit name="eclipseLinkPunitEmployee" transaction-type="RESOURCE_LOCAL">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<class>org.batch.model.data.EmployeeDO</class>
<exclude-unlisted-classes>true</exclude-unlisted-classes>
<properties>
<property name="javax.persistence.jdbc.driver" value="org.hsqldb.jdbcDriver"/>
<property name="javax.persistence.jdbc.url" value="jdbc:hsqldb:mem:dataSource"/>
<property name="javax.persistence.jdbc.user" value="sa"/>
<property name="javax.persistence.jdbc.password" value=""/>
<property name="eclipselink.ddl-generation" value="create-tables"/>
<property name="eclipselink.id-validation" value="NULL"/>
</properties>
</persistence-unit>
</persistence>
测试上下文 XML
<bean class="org.springframework.orm.jpa.JpaTransactionManager" id="transactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="persistenceUnitName" value="eclipseLinkPunitEmployee" />
<property name='dataSource' ref='junitDatasource' />
<property name="persistenceXmlLocation" value="classpath:JunitPersistence.xml" />
<property name="jpaPropertyMap">
<map>
<entry key="eclipselink.weaving" value="false" />
</map>
</property>
</bean>
<jdbc:embedded-database id="junitDatasource" type="HSQL">
<jdbc:script location="classpath:sequences.sql"/>
</jdbc:embedded-database>
sequences.sql
CREATE SEQUENCE SEQ_EMPLOYEE_ID START WITH 1 increment by 1;
CREATE TABLE DUAL (DUMMY DECIMAL);
INSERT INTO DUAL VALUES(1);
SET DATABASE SQL SYNTAX ORA TRUE;
最佳答案
native 序列对象特定于所使用的数据库 - 您需要指定用于 native 序列工作的正确数据库平台。您需要添加 target-database持久性属性来指定数据库(如果它不是从 Spring 获取或设置的)。
关于java - 出现错误 : platform DatabasePlatform does not support NativeSequence,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41827699/