请帮助我，我是 API 集成新手 我想显示 API 网址中的海报、标题和年份。 这是我尝试过的代码，当我登录时，它在数组中显示 JSON，但它在前端抛出未定义，请帮忙。
提前致谢
<html>
<head>
<link rel="stylesheet" type="text/css" href="css/style.css">
<link href="https://fonts.googleapis.com/css?family=Ubuntu" rel="stylesheet">
<meta name="viewport" content="width=device-width, initial-scale=1" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" />
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
<title>Welcome</title>
</head>
<body>
<div class="container">
<div class="table-responsive">
<h1>Movies</h1>
<table class="table table-bordered table-responsive table-striped" id="movies_table">
<tr>
<th>Poster</th>
<th>Name</th>
<th>Year</th>
</tr>
</table>
</div>
</div>
<div id="my_div" class="hide">"Thank You"</div>
</body>
<script>
$(document).ready(function(){
$.getJSON("http://www.omdbapi.com/?apikey=d8ecb486&s=red", function(data) {
console.log(data);
var movies = '';
$.each(data, function(key,value){
movies += '<tr>';
movies += '<td>'+value.poster+'</td>';
movies += '<td>'+value.title+'</td>';
movies += '<td>'+value.year+'</td>';
movies += '</tr>';
});
$('#movies_table').append(movies);
});
});
</script>
</html>
这是 API 结构
{"Search":[{"Title":"RED","Year":"2010","imdbID":"tt1245526","Type":"movie","Poster":"https://m.media-amazon.com/images/M/MV5BMzg2Mjg1OTk0NF5BMl5BanBnXkFtZTcwMjQ4MTA3Mw@@._V1_SX300.jpg"},{"Title":"Red Dragon","Year":"2002","imdbID":"tt0289765","Type":"movie","Poster":"https://m.media-amazon.com/images/M/MV5BMTQ4MDgzNjM5MF5BMl5BanBnXkFtZTYwMjUwMzY2._V1_SX300.jpg"},{"Title":"The Hunt for Red October","Year":"1990","imdbID":"tt0099810","Type":"movie","Poster":"https://m.media-amazon.com/images/M/MV5BY2Y5NWVjMmQtMWRmOC00ZTg3LWI3YWQtZGI2MWUwNWQ4OWQ2XkEyXkFqcGdeQXVyNDk3NzU2MTQ@._V1_SX300.jpg"},{"Title":"The Thin Red Line","Year":"1998","imdbID":"tt0120863","Type":"movie","Poster":"https://m.media-amazon.com/images/M/MV5BYjEzMTM2NjAtNWFmZC00MTVlLTgyMmQtMGQyNTFjZDk5N2NmXkEyXkFqcGdeQXVyNzQ1ODk3MTQ@._V1_SX300.jpg"},{"Title":"RED 2","Year":"2013","imdbID":"tt1821694","Type":"movie","Poster":"https://m.media-amazon.com/images/M/MV5BMjI2ODQ4ODY3Nl5BMl5BanBnXkFtZTcwNTc2NzE1OQ@@._V1_SX300.jpg"},{"Title":"Red Sparrow","Year":"2018","imdbID":"tt2873282","Type":"movie","Poster":"https://m.media-amazon.com/images/M/MV5BMTA3MDkxOTc4NDdeQTJeQWpwZ15BbWU4MDAxNzgyNTQz._V1_SX300.jpg"},{"Title":"Red Eye","Year":"2005","imdbID":"tt0421239","Type":"movie","Poster":"https://m.media-amazon.com/images/M/MV5BNzAxNjc1ODczOF5BMl5BanBnXkFtZTcwMjE3MjEzMw@@._V1_SX300.jpg"},{"Title":"Red Riding Hood","Year":"2011","imdbID":"tt1486185","Type":"movie","Poster":"https://m.media-amazon.com/images/M/MV5BMTc4NjYyMzQ5MV5BMl5BanBnXkFtZTcwNjE5Mjc3NA@@._V1_SX300.jpg"},{"Title":"Three Colors: Red","Year":"1994","imdbID":"tt0111495","Type":"movie","Poster":"https://m.media-amazon.com/images/M/MV5BYTg1MmNiMjItMmY4Yy00ZDQ3LThjMzYtZGQ0ZTQzNTdkMGQ1L2ltYWdlL2ltYWdlXkEyXkFqcGdeQXVyMTQxNzMzNDI@._V1_SX300.jpg"},{"Title":"Red Dawn","Year":"2012","imdbID":"tt1234719","Type":"movie","Poster":"https://m.media-amazon.com/images/M/MV5BMjI0MDAwMzA1M15BMl5BanBnXkFtZTcwNzIxMjY3OA@@._V1_SX300.jpg"}],"totalResults":"3993","Response":"True"}
最佳答案
有很多事情
首先，您的实际数据位于搜索数组下
其次，您要读取的键是从大写开始的
然后，如果您迭代搜索数组，键将是像 0,1,2...n 这样的索引，并且您需要从值中读取
只需更新此逻辑即可开始
var movies = '';
$.each(response.Search, function(key,value){
movies += `<tr>
<td>${value.Poster}</td>
<td>${value.Title}</td>
<td>${value.Year}</td>
</tr>`;
});
$('#movies_table').append(movies);
关于javascript - JSON 在 HTML 中抛出未定义的错误，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/61108525/