我正在尝试使用 SimpleXML
解析来解析下面的 XML
。
我已尝试以不同的方式解析 Element
的 Attributes
但无法成功解析以下 XML。
它会生成一个错误,列在底部。
<prestashop xmlns:xlink="http://www.w3.org/1999/xlink">
<order>
<id>1</id>
<id_address_delivery xlink:href="http://abc.com/add/1">1</id_address_delivery>
<id_address_invoice xlink:href="http://abc.com/add/2">2</id_address_invoice>
</order>
</prestashop>
Order.java
@Root(name="order")
@Namespace(reference="http://www.w3.org/1999/xlink",prefix="xlink")
public class Order {
@Element(name="id",required=true)
private int order_id;
@Element(name="id_address_delivery",required=false)
private int id_address_delivery;
@Attribute( name="href", required=false)
private String id_address_delivery_href;
@Element(name="id_address_invoice",required=false)
private int id_address_invoice;
@Attribute(name="href", required=false)
private String id_address_invoice_href;
}
OrderObject.java
public class OrderObject
{
@ElementList(required=true, inline=true)
private List<Order> list = new ArrayList<Order>();
public List<Order>getList()
{
return this.list;
}
}
我得到的异常是:
WARN/System.err(988): org.simpleframework.xml.core.PersistenceException:
Duplicate annotation of name 'href' on field 'id_address_delivery_href'
private java.lang.String com.prestashop.orders.Order.id_address_delivery_href
at org.simpleframework.xml.core.StructureBuilder.process(StructureBuilder.java:250)
at org.simpleframework.xml.core.StructureBuilder.process(StructureBuilder.java:173)
at org.simpleframework.xml.core.ObjectScanner.field(ObjectScanner.java:438)
at org.simpleframework.xml.core.ObjectScanner.scan(ObjectScanner.java:371)
at org.simpleframework.xml.core.ObjectScanner.<init>(ObjectScanner.java:82)
.
.
最佳答案
此异常的原因是您的两个 @Attribute
注释。它们不是设置到下一个元素,而是设置到整个 Order
对象。您的注释将设置 href
两次,但具有不同的值。
请参阅 @Attribute
的 JavaDoc :
The
Attribute
annotation represents a serializable XML attribute within an XML element. [...]
但是有一个很好且简单的解决方案:创建一个类来执行此操作,而不是组合元素和属性。
OrderObject
类:
@Root(name = "prestashop")
@Namespace(reference = "http://www.w3.org/1999/xlink", prefix = "xlink")
public class OrderObject
{
@ElementList(required = true, inline = true)
private List<Order> list;
public OrderObject()
{
this.list = new ArrayList<>();
}
public List<Order> getList()
{
return list;
}
// ...
@Override
public String toString()
{
return "OrderObject{" + "list=" + list + '}';
}
}
注意:这些类中的toString()
方法只是为了检查结果而实现的!
订单
类:
@Root(name = "order")
public class Order
{
@Element(name = "id")
private int id;
@Element(name = "id_address_delivery")
private AdressDelivery delivery;
@Element(name = "id_address_invoice")
private AdressInvoice invoice;
public Order(int id, AdressDelivery delivery, AdressInvoice invoice)
{
this.id = id;
this.delivery = delivery;
this.invoice = invoice;
}
private Order() { }
// Getter / Setter etc.
@Override
public String toString()
{
return "Order{" + "id=" + id + ", delivery=" + delivery + ", invoice=" + invoice + '}';
}
@Root()
public static class AdressDelivery
{
@Namespace(reference = "http://www.w3.org/1999/xlink", prefix = "xlink")
@Attribute(name = "href", required = false)
private String link;
@Text()
private int value;
public AdressDelivery(String link, int value)
{
this.link = link;
this.value = value;
}
AdressDelivery() { }
// Getter / Setter etc.
@Override
public String toString()
{
return "AdressDelivery{" + "link=" + link + ", value=" + value + '}';
}
}
@Root()
public static class AdressInvoice
{
@Attribute(name = "href", required = false)
@Namespace(reference = "http://www.w3.org/1999/xlink", prefix = "xlink")
private String link;
@Text()
private int value;
public AdressInvoice(String link, int value)
{
this.link = link;
this.value = value;
}
AdressInvoice() { }
// Getter / Setter etc.
@Override
public String toString()
{
return "AdressInvoice{" + "link=" + link + ", value=" + value + '}';
}
}
}
您可以看到结合了属性和元素的 AdressDelivery
和 AdressInvoice
类。您不必将它们实现为内部类;随意将它们写成“正常”的。您也不必将它们公开,甚至私有(private)也是可能的(例如,在 Order
的构造函数中构造它们。
但请注意 Order
类(及其内部类)中没有参数的空构造函数。它们是必需的。但是您可以将它们全部设为 private
- 无需公开它们。唯一重要的是您拥有一个不带参数的构造函数。
如何使用(示例):
File f = new File("whatever.xml");
Serializer ser = new Persister();
OrderObject orderObject = ser.read(OrderObject.class, f);
System.out.println(orderObject);
此代码解析文件中的 Xml 并打印反序列化的对象。
输入 Xml (如您的问题):
<prestashop xmlns:xlink="http://www.w3.org/1999/xlink">
<order>
<id>1</id>
<id_address_delivery xlink:href="http://abc.com/add/1">1</id_address_delivery>
<id_address_invoice xlink:href="http://abc.com/add/2">2</id_address_invoice>
</order>
</prestashop>
结果 (来自 println()
):
OrderObject{list=[Order{id=1, delivery=AdressDelivery{link=http://abc.com/add/1, value=1}, invoice=AdressInvoice{link=http://abc.com/add/2, value=2}}]}
没有清楚表示,但足以看到结果:-)
关于android - 如何通过 SimpleXML 解析 XML,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17166392/