我注意到来自 google play store 的其他拼图应用最多可以有 400 个独立的可移动拼图 block
我一直在尝试学习如何至少拍摄一张能代表我的谜题的图像， 裁剪某些部分并用拼图设计掩盖图像空间，以创建我的个人拼图
我想为我的应用程序最多使用 20 block ，但到目前为止，根据我的 android studio 内存日志，一旦位图工厂完成创建一个拼图 block ，在创建 20 block 拼图后，我用掉了大约 18mb 的内存该应用程序的所有其他功能我正在使用 400+mb 的内存，我必须使用“largeHeap=true”来防止内存不足，但我已经接近超过这些更高的限制，所以该应用程序非常棒缓慢而足够的动画 Activity 将不可避免地导致应用程序崩溃
我很想知道那些其他 Play 商店益智应用在做什么而我没有做
非常感谢任何输入
仅供引用，我的图像使用 PNG24，测试图像的尺寸为 556x720
这是一个例子，如果我只创建一个动画拼图图片
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
this.requestWindowFeature(Window.FEATURE_NO_TITLE);//Remove title bar
this.getWindow().setFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN, WindowManager.LayoutParams.FLAG_FULLSCREEN);//Hides notification bar
this.setContentView(R.layout.activity_main);//set content view AFTER ABOVE sequence (to avoid crash)
setRequestedOrientation(ActivityInfo.SCREEN_ORIENTATION_PORTRAIT);
mainDisplay = getWindowManager().getDefaultDisplay();
mainLayout = (ViewGroup) findViewById(R.id.id_layout);
DisplayMetrics m = new DisplayMetrics();
this.getWindowManager().getDefaultDisplay().getMetrics(m);
int windowHeight = m.heightPixels;
int windowWidth = m.widthPixels;
offsetX = (windowWidth / 1440.0f);
offsetY = (windowHeight / 2560.0f);
ourContext = this;
xpos = new float[2];
ypos = new float[2];
iv_PuzzleOne();
bkgdbm = BitmapFactory.decodeResource(getResources(), R.drawable.puzzleimage);
paintObject = new Paint();
paintObject.setXfermode(new PorterDuffXfermode(PorterDuff.Mode.XOR));
bm_PuzzleOne();
thisTimerTask = new ThisClass();
thisTimer = new Timer();
thisTimer.scheduleAtFixedRate(thisTimerTask, 16, 16);
touchpad = new ImageButton(this);
SetPos(0, 0, 1440, 2560);
touchpad.setLayoutParams(layoutPositioner);
touchpad.getBackground().setAlpha(1);
mainLayout.addView(touchpad);
touchpad.setOnTouchListener(new View.OnTouchListener() {
//@SuppressLint("NewApi")
@Override
public boolean onTouch(View v, MotionEvent event) {
if (event.getAction() == MotionEvent.ACTION_DOWN) {
xpos[0] = event.getX(); //storing my finger's position coordinates when I first touch the screen into the 1st element
ypos[0] = event.getY();
if ((event.getX() > imgx1) && (event.getX() < imgx1 + imagewidth1)
&& (event.getY() > imgy1) && (event.getY() < imgy1 + imageheight1)) {
touching1Puzzle = true;
img1.bringToFront();
}
}
if (event.getAction() == MotionEvent.ACTION_MOVE) {
xpos[1] = event.getX(); //add my finger's new current coordinates into the 2nd element
ypos[1] = event.getY();
if (touching1Puzzle) {
adjustImg();
}
}
if (event.getAction() == MotionEvent.ACTION_UP) {
if (touching1Puzzle) {
touching1Puzzle = false;
}
}
return false;
}
});
}
void bm_PuzzleOne()
{
//start of 1st puzzle
foregdimg1 = BitmapFactory.decodeResource(getResources(), R.drawable.puzzlepieceprac);//puzzle cut out (42.48MB) +6.15
mutableforegdimg1 = foregdimg1.copy(Bitmap.Config.ARGB_8888, true); //(48.32MB) +5.84
compositeImage1 = Bitmap.createBitmap(mutableforegdimg1);//cuts out foreground info into bkgdimage (54.43MB) +6.11
imgCanvas1 = new Canvas(compositeImage1); //canvas references puzzle cut out image (54.43MB) +0
imgCanvas1.drawBitmap(croppedBmp, null, new Rect(0, 0, 1500, 2000), paintObject);//places puzzle image on canvas (54.43MB) +0
img1.setImageBitmap(compositeImage1);
}
void iv_PuzzleOne()
{
img1 = new ImageView(ourContext);
SetPos(imgx1, imgy1, imagewidth1, imageheight1);
//bkgdimg.setImageResource(R.drawable.c);
//img1.setBackgroundColor(0xffF07305); //Orange
img1.setLayoutParams(layoutPositioner);
mainLayout.addView(img1);
}
void adjustImg()
{
if (touching1Puzzle)
{
if (xpos[1] > xpos[0]) //if the image had slid to the right
{
xPositionDifference = xpos[1] - xpos[0]; // find the difference in coordinate value between where my finger was and where it currently is
imgx1 += xPositionDifference; //add that difference to the current image position ...
xpos[0] += xPositionDifference; // ... store that difference for the next shift in finger postion
} else if (xpos[1] < xpos[0]) //if the image had slid to the left
{
xPositionDifference = xpos[0] - xpos[1]; // find the difference in coordinate value between where my finger was and where it currently is
imgx1 -= xPositionDifference; //subtract that difference to the current image position ...
xpos[0] -= xPositionDifference; // ... store that difference for the next shift in finger postion
}
if (ypos[1] > ypos[0]) //if the image had slid to the right
{
yPositionDifference = ypos[1] - ypos[0]; // find the difference in coordinate value between where my finger was and where it currently is
imgy1 += yPositionDifference; //add that difference to the current image position ...
ypos[0] += yPositionDifference; // ... store that difference for the next shift in finger postion
} else if (ypos[1] < ypos[0]) //if the image had slid to the left
{
yPositionDifference = ypos[0] - ypos[1]; // find the difference in coordinate value between where my finger was and where it currently is
imgy1 -= yPositionDifference; //subtract that difference to the current image position ...
ypos[0] -= yPositionDifference; // ... store that difference for the next shift in finger postion
}
}
}
class ThisClass extends TimerTask {
@Override
public void run() {
MainActivity.this.runOnUiThread(new Runnable() {
@Override
public void run() {
if(touching1Puzzle)
{SetPos(imgx1, imgy1, imagewidth1, imageheight1);
img1.setLayoutParams(layoutPositioner);}
}
});
}
}
public void SetPos(float x, float y, float width, float height) {
layoutPositioner = new RelativeLayout.LayoutParams(RelativeLayout.LayoutParams.WRAP_CONTENT, RelativeLayout.LayoutParams.WRAP_CONTENT);
layoutPositioner.topMargin = (int) (offsetY * y);
layoutPositioner.leftMargin = (int) (offsetX * x);
layoutPositioner.width = (int) (width * offsetX);
layoutPositioner.height = (int) (height * offsetY);
}
这是我加载 5 张图片时的样子
http://s15.postimg.org/ymqspk77v/Screenshot_2016_02_29_07_19_26.png
最佳答案
好吧，让我们看看。
首先你不需要这么大的拼图，所以你可以缩小它们:
来自 http://developer.android.com/training/displaying-bitmaps/load-bitmap.html
To tell the decoder to subsample the image, loading a smaller version into memory, set inSampleSize to true in your BitmapFactory.Options object. For example, an image with resolution 2048x1536 that is decoded with an inSampleSize of 4 produces a bitmap of approximately 512x384. Loading this into memory uses 0.75MB rather than 12MB for the full image (assuming a bitmap configuration of ARGB_8888)
其次，您应该尝试在 AsyncTask 中加载位图以防止应用程序卡住。
第三，您可以使用 LruCache 缓存您的位图以加快速度
http://developer.android.com/training/displaying-bitmaps/cache-bitmap.html
private LruCache<String, Bitmap> mMemoryCache;
@Override
protected void onCreate(Bundle savedInstanceState) {
...
// Get max available VM memory, exceeding this amount will throw an
// OutOfMemory exception. Stored in kilobytes as LruCache takes an
// int in its constructor.
final int maxMemory = (int) (Runtime.getRuntime().maxMemory() / 1024);
// Use 1/8th of the available memory for this memory cache.
final int cacheSize = maxMemory / 8;
mMemoryCache = new LruCache<String, Bitmap>(cacheSize) {
@Override
protected int sizeOf(String key, Bitmap bitmap) {
// The cache size will be measured in kilobytes rather than
// number of items.
return bitmap.getByteCount() / 1024;
}
};
...
}
public void addBitmapToMemoryCache(String key, Bitmap bitmap) {
if (getBitmapFromMemCache(key) == null) {
mMemoryCache.put(key, bitmap);
}
}
public Bitmap getBitmapFromMemCache(String key) {
return mMemoryCache.get(key);
}
这应该足够了，但如果还不够的话，这里有所有来源，还有一些额外的: http://developer.android.com/training/displaying-bitmaps/index.html
你也可以尝试使用
void bm_PuzzleOne()
{
//start of 1st puzzle
BitmapFactory.Options opt = new BitmapFactory.Options();
//makes a loaded image mutable
opt.inMutable=true;
//reduces density to that of screen
opt.inTargetDensity = this.context.getResources().getDisplayMetrics().densityDpi;
opt.inScaled=true;
//makes bitmap half as big
opt.inSampleSize=2;
//foregdimg1 = BitmapFactory.decodeResource(getResources(), R.drawable.puzzlepieceprac);//puzzle cut out (42.48MB) +6.15
mutableforegdimg1 = BitmapFactory.decodeResource(getResources(), R.drawable.puzzlepieceprac,opt)
compositeImage1 = Bitmap.createBitmap(mutableforegdimg1);//cuts out foreground info into bkgdimage (54.43MB) +6.11
imgCanvas1 = new Canvas(compositeImage1); //canvas references puzzle cut out image (54.43MB) +0
imgCanvas1.drawBitmap(croppedBmp, null, new Rect(0, 0, 1500, 2000), paintObject);//places puzzle image on canvas (54.43MB) +0
img1.setImageBitmap(compositeImage1);
}
代替
void bm_PuzzleOne()
{
//start of 1st puzzle
foregdimg1 = BitmapFactory.decodeResource(getResources(), R.drawable.puzzlepieceprac);//puzzle cut out (42.48MB) +6.15
mutableforegdimg1 = foregdimg1.copy(Bitmap.Config.ARGB_8888, true); //(48.32MB) +5.84
compositeImage1 = Bitmap.createBitmap(mutableforegdimg1);//cuts out foreground info into bkgdimage (54.43MB) +6.11
imgCanvas1 = new Canvas(compositeImage1); //canvas references puzzle cut out image (54.43MB) +0
imgCanvas1.drawBitmap(croppedBmp, null, new Rect(0, 0, 1500, 2000), paintObject);//places puzzle image on canvas (54.43MB) +0
img1.setImageBitmap(compositeImage1);
}
关于android - 如何在不耗尽内存的情况下在 droid 中制作益智应用程序？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/35706406/