php - 使用 jquery 访问表中的值时出现问题

Question

嘿伙计们，我正在尝试从表中获取特定名称。这是我的代码:

$(document).ready(function () {
    $("#NotesAccessor").click(function () {
      var notes_name = $(this).document.getElementById("#user_table");
      alert(notes_name);
      run();
    });
});

这是上面的内容，这是我尝试使用 #notesAccessor 单击表行的关联用户名

表:

 .........
    <td>
        $csvusername
    </td>
.........
    <td>
    ";
      if ($checkNotes[1] == 'No')
    {
        echo "None";
    }
    if ($checkNotes[1] == 'Yes')
    {
            echo "<a href='#' id='NotesAccessor'>Click to access</a>";
    }
    echo "
    </td>
........

我的问题是 - 如何获取关联 NotesAccessor 的 $csvusername，以便我可以将其发送到 Jquery 中的对话框并打开我需要获取的那个人的笔记。

希望这是有道理的。

更新:

这是完整的表格:

<table class='results'>
    <tr class='firsttr' style='background:gray;'>
        <td>First Name</td>
        <td>Last Name</td>
        <td>Email</td>
        <td>Phone</td>
        <td>Username</td>
        <td>Password</td>
        <td>Status</td>
        <td>Combined Single Limit</td>
        <td>Bodily Injury Each Person</td>
        <td>Bodily Injury Each Accident</td>
        <td>Property Damage</td>
        <td>Address</td>
        <td>Notes</td>
        <td>#</td>
    </tr>"; $j = 0; while ($row = $sth->fetch(PDO::FETCH_ASSOC)) { $val = 1; $csvfirst
    = $row; $csvfirstname = $csvfirst['firstname']; $csvlastname = $csvfirst['lastname'];
    $csvemail = $csvfirst['email']; $csvphone = $csvfirst['phone']; $csvusername
    = $csvfirst['username']; $csvpassword= $csvfirst['password']; $csvstatus
    = $csvfirst['status']; $csvnotes = $csvfirst['notes']; $csl = $csvfirst['Combinedlimit'];
    $bodyinj = $csvfirst['bodyinjur']; $eachacc = $csvfirst['bodyinjureachacc'];
    $propertydmg = $csvfirst['propertydmg']; // Select the current employees
    address $psql = "SELECT MailingAdrs FROM insuranceverificationdisclaimer
    WHERE TraineeUsername =:user"; $psth= $DBH->prepare($psql); $psth->execute(array(':user'
    => $csvusername )); while ($prow = $psth->fetch(PDO::FETCH_ASSOC)) { $pcheck
    = $prow; $address = $pcheck['MailingAdrs']; } if ($csvstatus != "No Longer
    Work Here" && $csvstatus == "Confirmed"){ //check to see if notes exist
    if (empty($csvnotes)) { $checkNotes = 0; } else { $checkNotes = 1; } $memberfirstnamearray[$j]
    = $csvfirstname; $memberlastnamearray[$j] = $csvlastname; $memberemailarray[$j]
    = $csvemail; $memberphonearray[$j] = $csvphone; $membercsl[$j] = $csl;
    $memberbodyinj[$j] = $bodyinj; $membereachacc[$j] = $eachacc; $memberpropertydmg[$j]
    = $propertydmg; $memberstatus[$j] = $csvstatus; $memberaddress[$j] = $address;
    $j++; $i++; echo "
    <tr>
        <td>$csvfirstname</td>
        <td>$csvlastname</td>
        <td>$csvemail</td>
        <td>$csvphone</td>
        <td class='user_table'>$csvusername</td>
        <td>$csvpassword</td>
        <td>$csvstatus</td>
        <td>$csl</td>
        <td>$bodyinj</td>
        <td>$eachacc</td>
        <td>$propertydmg</td>
        <td>$address</td>
        <td>"; if ($checkNotes == 0) { echo "None"; } if ($checkNotes == 1) { echo
            "<a href='#' id='NotesAccessor'>Click to access</a>"; } echo "</td>
        <td>$i</td>
    </tr>"; } }
</table>

Answer 1

您将纯 JavaScript 与 jQuery 混合在一起，可以按如下方式解决。

首先，你可以放一个类来标识<td>与 $csvusername ，例如class='td_with_csvusername'然后执行以下操作:

$(document).ready(function () {
    $(".NotesAccessor").on("click", function () {
        var td = $(this).parent().parent().find(".td_with_csvusername");
        alert(td.html());
    });
});