jquery - 如何使用AJAX get请求正确传递参数

Question

我正在以这种方式发出 AJAX get 请求

$(document).on("click", ".topp", function () 
{
 var id_attr_val = $(this).attr("id");
 alert(id_attr_val);
 $.ajax({
            type: 'GET',
            url: 'http://hostip:8080/OrderSnacks/oms/toppings',
            jsonpCallback: 'jsonCallback',
            dataType: 'jsonp',
            data : "topping="+id_attr_val+"",
            jsonp: false,
            success: function (response) {
             console.log(response);
            },
            error: function (e) {
                $("#divResult").html("WebSerivce unreachable");
            }
        });
});

警报值显示为59，但是当我在控制台中观察时，它以这种方式进行调用

http://hostip:8080/OrderSnacks/oms/toppings?topping=59&_=1402670107061

你能告诉我如何发送 59 ，而不是那些额外的字符吗？

Answer 1

要“删除”&_=1402670107061 部分，您必须在 ajax 请求中设置以下内容:

cache: true,

而且，是的，您仍然可以使用数据:{topping: id_attr_val },。

cache (default: true, false for dataType 'script' and 'jsonp') Type: Boolean If set to false, it will force requested pages not to be cached by the browser. Note: Setting cache to false will only work correctly with HEAD and GET requests. It works by appending "_={timestamp}" to the GET parameters. The parameter is not needed for other types of requests, except in IE8 when a POST is made to a URL that has already been requested by a GET.