当用户单击链接时,它使用 jquery ajax 提交表单以转到 PayPal。由于某种原因它不起作用。我感谢任何帮助。
HTML 链接:
<a href="#" onClick="javascript:go_paypal();">Paypal</a>
JS函数:
function go_paypal() {
data = 'req_paypal=1';
$.blockUI({ message: '<h1> Going to Paypal...</h1>',css:{background:'#000'} });
$.ajax({
type: "POST",
url: "index.php",
data: data,
success: function(data) { $("#paypal_form").html(data); $("#payPalForm").submit(); } ,
error: function() {$.unblockUI(); alert('Unable to communicate to server.'); }
});
return false;
}
PHP 代码:
if(isset($_POST['req_paypal']) && $_POST['req_paypal'] == 1 ) {
$sql = 'INSERT INTO `transactions` (id,type,ip,time,ammount,status) VALUES (NULL,1,\''.$_SERVER['REMOTE_ADDR'].'\',\''.time().'\',\''.$global['paypal_prod_amount'].'\',0) ';
echo $sql;
// $sql2 = 'INSERT INTO `users` (id,email,password,referred_by,referrals) VALUES ('',)';
mysql_query($sql);
$id = mysql_insert_id();
$html = '
<form action="https://www.sandbox.paypal.com/cgi-bin/webscr" method="post" id="payPalForm">
<input type="hidden" name="item_number" value="One Year of Imgur Pro">
<input type="hidden" name="cmd" value="_xclick">
<input type="hidden" name="no_note" value="1">
<input type="hidden" name="business" value="'.$global['paypal_email'].'">
<input type="hidden" name="custom" value="'.base64_encode($id).'">
<input type="hidden" name="currency_code" value="USD">
<input type="hidden" name="return" value="'.$global['paypal_return'].'">
<input name="item_name" type="hidden" id="item_name" value="One Year of Imgur Pro" >
<input name="amount" type="hidden" id="amount" value="'.$global['paypal_prod_amount'].'" >
</form>
';
echo $html;exit;
}
最佳答案
看起来在您的 success
函数中,您正在将 global 变量 data
传递给 html()
。尝试更仔细地命名您的变量。
试试这个:
function go_paypal() {
var postData = 'req_paypal=1';
$.blockUI({ message: '<h1> Going to Paypal...</h1>',css:{background:'#000'} });
$.ajax({
type: "POST",
url: "index.php",
data: postData,
success: function(data) { $("#paypal_form").html(data); $("#payPalForm").submit(); },
error: function(e) {$.unblockUI(); alert('Unable to communicate to server.'); }
});
return false;
}
关于php - 我在使用 jquery 提交表单时遇到问题。之前可以正常工作;/,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2796700/