我一直在努力禁止父类 li 打开其中放置了链接的选项卡,我只想使用“保存并继续”按钮来打开选项卡而不是链接,导致选项卡更改后链接无法禁用。以前的选项卡被禁用,请问我该如何解决这个问题。只有“保存”和“继续”按钮才能移动并返回选项卡
//the html
<div class="wizard">
<div class="wizard-inner">
<div class="connecting-line"></div>
<ul class="nav nav-tabs" role="tablist">
<li role="presentation" class="active" id="step_1">
<a href="#step1" data-toggle="tab" aria-controls="step1" role="tab" title="Step 1">
<span class="round-tab">
<div class="numberCircle">1</div>
</span>
</a>
</li>
<li role="presentation" class="disabled" id="step_2">
<a href="#step2" data-toggle="tab" aria-controls="step2" role="tab" title="Step 2">
<span class="round-tab">
<div class="numberCircle">2</div>
</span>
</a>
</li>
<li role="presentation" class="disabled" id="step_3">
<a href="#step3" data-toggle="tab" aria-controls="step3" role="tab" title="Step 3">
<span class="round-tab">
<div class="numberCircle">3</div>
</span>
</a>
</li>
<li role="presentation" class="disabled" id="step_4">
<a href="#complete" data-toggle="tab" aria-controls="complete" role="tab" title="Complete">
<span class="round-tab">
<div class="numberCircle">4</div>
</span>
</a>
</li>
</ul>
</div>
<div class="tab-pane active" role="tabpanel" id="step1"><li><button type="button" class="btn btn-default prev-step" style="margin-top:-30px;">Previous</button></li>
<li><button type="button" class="btn-info-full next-step" style="margin-top:-30px;">Save and continue</button></li></div>
<div class="tab-pane" role="tabpanel" id="step2"><li><button type="button" class="btn btn-default prev-step" style="margin-top:-30px;">Previous</button></li>
<li><button type="button" class="btn-info-full next-step" style="margin-top:-30px;">Save and Continue</button></li></div>
<div class="tab-pane" role="tabpanel" id="step3"><li><button type="button" class="prev-step" style="margin-top:-30px;">Previous</button></li>
<li><button type="button" class="btn btn-success btn-info-full next-step" style="margin-top:-30px;">Save and Finish</button></li></div>
</div>
</div>
</div>
</div>
//The js tab script
<script>
$(document).ready(function () {
//Initialize tooltips
$('.nav-tabs > li a[title]').tooltip();
//Wizard
$('a[data-toggle="tab"]').on('show.bs.tab', function (e) {
var $target = $(e.target);
if ($target.parent().hasClass('disabled')) {
return false;
}
});
$(".next-step").click(function (e) {
var $active = $('.wizard .nav-tabs li.active');
$active.next().removeClass('disabled');
nextTab($active);
var current_tab = e.target; //GOT CURRENT TAB
var previous_tab = e.relatedTarget; //GOT PREVIOUS TAB
$previous_tab.parent().addClass('disabled'); //WHAT I TRIED
});
$(".prev-step").click(function (e) {
var $active = $('.wizard .nav-tabs li.active');
prevTab($active);
});
});
function nextTab(elem) {
$(elem).next().find('a[data-toggle="tab"]').click();
}
function prevTab(elem) {
$(elem).prev().find('a[data-toggle="tab"]').click();
}
</script>
最佳答案
我建议在您的链接上设置一个自定义点击事件。具有 data-toggle='tab' 和 role='tab' 表示 Bootstrap 您希望根据这些链接切换选项卡。因此,我不会在“选项卡显示事件”上注册监听器,而是这样做:
$("data-toggle='tab'").on("click", function(e) {
return $(this).closest("li").hasClass("active");
});
然后,对父级“不活动”的链接的任何点击都不会产生任何效果。
关于jquery - 更改选项卡后禁用从链接 Bootstrap 打开选项卡,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49090634/