php - 无法初始化 Fancybox 和 PHP

Question

我在脚本中安装了 fancybox，但由于某种原因，它没有单击弹出窗口，而是单击了图像的位置。我通过一些以数字方式生成的 php 代码(基于数据库中的信息)运行它。因此，虽然有多个代码块，但其本质上是相同的代码。我只是不知道如何让它发挥作用任何建议都会很棒。我的代码如下。

<?php 
if(isset($_GET['package'])) {
    $package = ($_GET['package']);
    $arr = array();
    $items = "SELECT * FROM ind_products";
    $item_list = mysql_query($items);
    /*$row = mysql_fetch_array($item_list);*/
    while($row = mysql_fetch_array($item_list)) {
        $arr = explode(',',$row['packages']);
        if (in_array("$package",$arr)) {

        echo "<form action=\"\" method=\"post\" class=\"jcart\" >";
        echo "<div id=\"itemBox\" align=\"left\">";
        $item_name = ($row['item_name']);
        $size = ($row['size']);
        $description = ($row['description']);
        $id = ($row['id']);
        $photo = ($row['photo']);
        $photo2 = ($row['photo2']);

        if ($photo == '') {
            $photo = 'images/pph.jpg';
        }
        if ($photo2 == '') {
            $photo2 = 'images/pph2.jpg';
        }
        if ($description == '') {
            $description = 'Description goes here!';
        }
        echo "<input type=\"hidden\" name=\"my-item-id\" value=\"$id\">";       
        echo "<input type=\"hidden\" name=\"my-item-name\" value=\"$item_name\">";  
        echo "<input type=\"hidden\" name=\"my-item-price\" value=\"0.00\">";   
        echo "<input type=\"hidden\" name=\"my-item-url\" value=\"\">"; 

        echo "<p id=\"info_image\">";
        echo "<a id=\"single_1\" href=\"$photo2\">";
        echo "<img src=\"crop.php?h=85&w=85&f=$photo\" align=\"left\" alt=\"item images\" />";
        echo "</a>";
        echo "</p>";

        echo "<p id=\"info_box\">";
        echo "<span id=\"pro_name\">",$item_name,"</span>",'<br>';
        echo "<span id=\"pro_size\">",$size,"</span>",'<br>';
        echo "<span id=\"pro_des\">",$description,'<br>';   
        echo "<span id=\"pro_title\">Quantity</span><input name=\"my-item-qty\" type=\"text\" value=\"1\" size=\"3\" />";
        echo "<span id=\"pro_input\"></span><input type=\"submit\" name=\"my-add-button\" value=\"add to inquiry\" class=\"button\" />";    
        echo "</p>";
        echo "<div style=\"clear:both; margin-bottom:0.5em\"></div>";
        echo "</div>";
        echo "</form>";
        }else{

        // do nothing for now


        /*echo "<form action=\"\" method=\"post\" class=\"jcart\" >";
        echo "<div id=\"itemBox\" align=\"left\">";
        $item_name = ($row['item_name']);
        $size = ($row['size']);
        $description = ($row['description']);
        $id = ($row['id']);


        echo "<span id=\"pro_name\">",$item_name,"</span>",'<br>';
        echo "<span id=\"pro_size\">",$size,"</span>",'<br>';
        echo "<span id=\"pro_des\">",$description,'<br>';
        echo 'There are no products to display!!';
        echo "<div style=\"clear:both; margin-bottom:0.5em\"></div>";
        echo "</div>";
        echo "</form>"; */
        }
    }
}else{
    echo 'The packages are not set';
}
?>

fancybox 代码:

$(document).ready(function() {

       $("#single_1").fancybox({
          helpers: {
              title : {
                  type : 'float'
              }
          }
      });
});

Answer 1

您确定所有必需的脚本(jquery + fancybox)以及所有附加加载的 js 脚本/代码都已加载/初始化且没有错误吗？ 在 fancybox-setup-call 之前发生的任何 javascript 错误都会阻止其成功启动。