php - AJAX Jquery PHP 表单验证

Question

我想创建一个基于 jquery 验证插件 ( http://docs.jquery.com/Plugins/Validation ) 的评论表单。如何配置表单以使用 AJAX 提交？现在我无法在不进入下一页(process.php)的情况下提交表单。我希望它保留在表单页面上。

当前代码几乎直接来自 jquery。

<script>
    $(document).ready(function () {
        $("#commentForm").submit(function () {
            if ($("#commentForm").validate()) {
                $.ajax({
                    type: 'POST',
                    url: 'process.php',
                    data: $(this).serialize(),
                    success: function (returnedData) {
                        $('#commentForm').append(returnedData);
                    }
                });
            }
            return false;
        });
    });
</script>


<form class="cmxform" id="commentForm" method="POST" action="process.php">
<label for="cname">Name</label>
<em>*</em><input id="cname" name="name" size="25" class="required" minlength="2" />

<label for="cemail">E-Mail</label>
<em>*</em><input id="cemail" name="email" size="25"  class="required email" />

<label for="curl">URL</label>
<em>  </em><input id="curl" name="url" size="25"  class="url" value="" />
<label for="ccomment">Your comment</label>
<em>*</em><textarea id="ccomment" name="comment" cols="22"  class="required"></textarea>

<input class="submit" type="submit" value="Submit"/>

PHP 也非常标准:

<?php

$to      = '<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="8cffe8eaffede8eaffffeaedffe8ccebe1ede5e0a2efe3e1" rel="noreferrer noopener nofollow">[email protected]</a>';
$subject = 'the subject';
$message = 'hello';
$headers = 'From: <a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="1c6b797e717d6f68796e5c79647d716c7079327f7371" rel="noreferrer noopener nofollow">[email protected]</a>' . "\r\n" .
'Reply-To: <a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="d9aebcbbb4b8aaadbcab99bca1b8b4a9b5bcf7bab6b4" rel="noreferrer noopener nofollow">[email protected]</a>' . "\r\n" .
'X-Mailer: PHP/' . phpversion();

mail($to, $subject, $message, $headers);

print "Form submitted successfully: <br>Your name is <b>".$_POST['cname']."</b> and your email is <b>".$_POST['email']."</b><br>";
?>

感谢您的帮助。

Answer 1

$(document).ready(function(){
    $("#commentForm").submit(function(){
        if($("#commentForm").validate()){
            $.ajax({
                type: 'POST',
                url: 'process.php',
                data: $(this).serialize(),
                success: function(returnedData){
                    alert(returnedData);
                }
            });
        }
        return false;
    });
});