jquery 创建数组，其中包含天数和 OT 的总和，后跟项目编号

Question

我想生成如下 JSON 数组。

完整详细的数组；

MyArray = [{ prj : "P1", days : "8", ot : "2" }, { prj : "P2", days : "8", ot : "2" }, { prj : "P2", days : "8", ot : "2" }, { prj : "P1", days : "8", ot : "2" }{prj : "P3", days : "8", ot : "2" }, { prj : "P2", days : "8", ot : "2" }, { prj : "P3", days : "8", ot : "2" }];

但我想将其压缩如下；

MyArray = [{ prj : "P1", days : "16", ot : "4" }, { prj : "P2", days : "24", ot : "6" }, { prj : "P3", days : "16", ot : "4" }];

如果project_number存在，应该得到天数和加类时间的总和；

See the example

Answer 1

试试这个，这会满足您的需要。

var MyArray = [];

//This will be used to construct your JSON object
function ConstructJson(prj, days, ot) {

    var xObj = {};
    xObj.prj = prj;
    xObj.days = days;
    xObj.ot = ot;

    MyArray[MyArray.length] = xObj;

}

 //This will minimise your json object.
function MinimiseJson() {

    var xTempArray = [];
    var xTempObj = {};
    var xPrj = '';

    for (var i = 0; i < MyArray.length; i++) {

        if (xPrj == '' && MyArray[i]) {

            xPrj = MyArray[i].prj;

            xTempObj.prj = xPrj;
            xTempObj.days = MyArray[i].days;
            xTempObj.ot = MyArray[i].ot;

            for (var j = i + 1; j < MyArray.length; j++) {

                if (MyArray[j] && MyArray[j].prj == xPrj) {

                    xTempObj.days += MyArray[j].days;
                    xTempObj.ot += MyArray[j].ot;

                    MyArray[j] = null;
                }

            }

            xPrj = '';
            xTempArray[xTempArray.length] = xTempObj;
            xTempObj = {};
        }
    }

    return xTempArray;

}

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