jQuery 根据另一个数组从数组中删除多个对象

Question

我有一个数组，其中包含名称列表。如果这些名称与另一个数组中的键/值对匹配，我想删除包含匹配项的对象并返回没有该对象的数组。

这是我到目前为止的一个例子:

var supervisorsToRemove = ["Supervisor1", "Supervisor2"];
var data = [{id: "Name1", supervisor: "Supervisor1"},{id: "Name2", supervisor: "Supervisor1"},{id: "Name3", supervisor: "Supervisor2"},{id: "Name4", supervisor: "Supervisor3"}]

我希望生成的数据数组为:

data = [{id: "Name4", supervisor: "Supervisor3"}]

我可以通过以下方式删除一位主管的对象:

var supervisorsToRemove = "Supervisor1";
data = $.grep(data, function(e){ 
     return e.supervisor != supervisorsToRemove; 
});

但是当我尝试删除数组中的所有内容时，它不起作用:

var supervisorsToRemove = ["Supervisor1","Supervisor2"];
data = $.grep(data, function(e){ 
     return e.supervisor != supervisorsToRemove; 
});

Answer 1

使用Array#indexOf方法(或 Array#includes 方法)检查​​数组中存在的元素

data = $.grep(data, function(e){ 
  return supervisorsToRemove.indexOf(e.supervisor) == -1; 
  // or return supervisorsToRemove.includes(e.supervisor); 
});

var supervisorsToRemove = ["Supervisor1", "Supervisor2"];
var data = [{
  id: "Name1",
  supervisor: "Supervisor1"
}, {
  id: "Name2",
  supervisor: "Supervisor1"
}, {
  id: "Name3",
  supervisor: "Supervisor2"
}, {
  id: "Name4",
  supervisor: "Supervisor3"
}]
console.log($.grep(data, function(e) {
  return supervisorsToRemove.indexOf(e.supervisor) == -1;
  // or return supervisorsToRemove.includes(e.supervisor); 
}));

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

---

更好的方法是使用一个将主管值作为属性的对象，这将有助于加快速度，因为 Array#indexOf方法较慢。

var supervisorsToRemove = {"Supervisor1" : true, "Supervisor2" : true };

data = $.grep(data, function(e){ 
  return !supervisorsToRemove[e.supervisor]; 
});

var data = [{
  id: "Name1",
  supervisor: "Supervisor1"
}, {
  id: "Name2",
  supervisor: "Supervisor1"
}, {
  id: "Name3",
  supervisor: "Supervisor2"
}, {
  id: "Name4",
  supervisor: "Supervisor3"
}]
var supervisorsToRemove = {
  "Supervisor1": true,
  "Supervisor2": true
};

console.log(
  $.grep(data, function(e) {
    return !supervisorsToRemove[e.supervisor];
  })
);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

如果您无法控制数组，则使用 Array#reduce 生成对象方法。

var obj = supervisorsToRemove.reduce(function(obj, v){ obj[v] = true; return obj; }, {});

data = $.grep(data, function(e){ 
  return !obj[e.supervisor]; 
});

var supervisorsToRemove = ["Supervisor1", "Supervisor2"];
var data = [{
  id: "Name1",
  supervisor: "Supervisor1"
}, {
  id: "Name2",
  supervisor: "Supervisor1"
}, {
  id: "Name3",
  supervisor: "Supervisor2"
}, {
  id: "Name4",
  supervisor: "Supervisor3"
}]
var supervisorsToRemove = {
  "Supervisor1": true,
  "Supervisor2": true
};


var obj = supervisorsToRemove.reduce(function(obj, v) {
  obj[v] = true;
  return obj;
}, {});

console.log(
  $.grep(data, function(e) {
    return !obj[e.supervisor];
  })
);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

---

您甚至可以使用 native Javascript Array#filter方法。

var supervisorsToRemove = ["Supervisor1", "Supervisor2"];
var data = [{
  id: "Name1",
  supervisor: "Supervisor1"
}, {
  id: "Name2",
  supervisor: "Supervisor1"
}, {
  id: "Name3",
  supervisor: "Supervisor2"
}, {
  id: "Name4",
  supervisor: "Supervisor3"
}]
var supervisorsToRemove = {
  "Supervisor1": true,
  "Supervisor2": true
};

console.log(
  data.filter(function(e) {
    return !supervisorsToRemove[e.supervisor];
  })
);