您好，我正在努力获取 JSON 格式的经过验证的错误消息。我不知道为什么在 Laravel 中做到这一点如此困难。我正在尝试使用 ajax 请求来获取包含表单数据错误的 HTTP 响应。这是我的请求代码
<?php
namespace App\Http\Requests;
use App\Http\Requests\Request;
use Auth;
use Log;
class PostRequest extends Request
{
/**
* Determine if the user is authorized to make $this request.
*
* @return bool
*/
public function authorize()
{
return true;
}
/**
* Get the validation $rules that apply to the request.
*
* @return array
*/
public function wantsJson()
{
return true;
}
public function response(array $errors)
{
if ($this->ajax())
{
return new JsonResponse($errors, 422);
}
return $this->redirector->to($this->getRedirectUrl())
->withInput($this->except($this->dontFlash))
->withErrors($errors);
}
public function rules() {
$rules = [];
foreach($this->request->get('address') as $key => $val) {
$rules['address.'.$key] = 'required';
}
foreach($this->request->get('city') as $key => $val) {
$rules['city.'.$key] = 'required';
}
return $rules;
}
public function messages() {
foreach($this->request->get('address') as $key => $val) {
$messages['address.'.$key.'.required']="*Please fill in the address";
}
foreach($this->request->get('city') as $key => $val) {
$messages['city.'.$key.'.required']="*Please fill in the city";
}
return $messages;
}
}
这是我的 Controller 代码
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Http\Requests;
use App\Http\Requests\PostRequest;
use Auth;
class propContoller extends Controller {
public function __construct() {
$this->middleware('auth');
}
public function main () {
$amount = Auth::user()->units; // pull amount of units from data base and create forms
return view("myprop",compact("amount"));
}
public function Postdata(PostRequest $request) {
}
}
和我的ajax请求
$("#from").submit(function(event) {
$.ajax({
type: 'post',
url: '/myproperties/save',
data: { '_token': token, 'data': "good" },
dataType: 'json',
success: function(data){
console.log(data);
},
error: function(data){
var errors = data.responseJSON;
console.log(errors);
// Render the errors with js ...
}
});
和我的 HTML
<div class="form-group col-md-6">
<div class= "col-md-6 form-group {{ $errors->has('address.'.$i) ? ' has-error' : '' }}">
<label for={{$id = "Address".$i}}>Address</label>
<input value="{{ old('address.'.$i) }}" type="text" name="address[{{$i}}]" class="form-control" id={{$id = "Address".$i}} placeholder="Street Address">
@if ($errors->has('address.'.$i))
<span class="help-block">
<strong>{{ $errors->first('address.'.$i) }}</strong>
</span>
@endif
</div>
<div class="col-md-6 form-group {{ $errors->has('city.'.$i) ? ' has-error' : '' }}">
<label for={{$id = "city".$i}}>City</label>
<input value="{{ old('city.'.$i) }}" type="text" name="city[{{$i}}]" class="form-control" id={{$id = "City".$i}} placeholder="City">
@if ($errors->has('city.'.$i))
<span class="help-block">
<strong>{{ $errors->first('city.'.$i) }}</strong>
</span>
@endif
</div>
请有人帮助我，我对 Laravel 很菜鸟，所以对我宽容点
谢谢!
最佳答案
你错了。在 Laravel 中创建 JSON 响应非常容易，以便稍后您的前端玩具可以使用它。
public function getSomethingById(string $id)
{
$data = $this->fooRepository
->getSomething($id)
->pluck('name', 'id')
->toArray(); // you don't have to use repository, you can use Eloquent directly here, or DB facade or even hardcode the array.
return response()->json([
'count' => count($data),
'data' => $data // or whatever
]);
}
无论您需要什么，只要记住 response()->json() 需要一个数组。 Laravel 将返回具有正确 mime 类型的 JSON 响应。
然后你可以使用 jQuery $.get() 你的 AJAX 资源等
关于jquery - 让 Laravel 返回 JSON，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/37127182/