JQuery 分割逗号与 ashx 处理程序分隔

Question

我在将逗号分隔的字符串拆分为数组时遇到问题。在我的 ashx 处理程序页面中，我的字符串如下所示:

context.Response.Write(string.Format("{0},{1},{2},{3},{4},{5},{6},{7},{8},{9} ", BusProfileID, BusinessName, BusinessPhone, BusinessEmail, BusinessAddress, BusinessCity, BusinessState, BusinessZip, BusinessWebsite, BusinessCategory));

当我尝试做一个数组时，结果没有显示。

   <script>
        $(document).ready(function () {
            $('#ContentPlaceHolder1_businessSelect').change(function () {
                $.ajax({
                    contentType: "text/html; charset=utf-8",
                    data: "ID=" + $('#ContentPlaceHolder1_businessSelect').val(),
                    url: "getBusValue.ashx",
                    dataType: "text",
                    success: function (data) {
                    var vardata = JSON.stringify(data)
                    var arr = vardata.split(',')
                    $("#ContentPlaceHolder1_BusProfileID").val(arr[0]);
                    $("#ContentPlaceHolder1_BusinessName").val(arr[1];
                    $("#ContentPlaceHolder1_BusinessPhone").val(arr[2]);
                    $("#ContentPlaceHolder1_BusinessEmail").val(arr[3]);
                    $("#ContentPlaceHolder1_BusinessAddress").val(arr[4]);
                    $("#ContentPlaceHolder1_BusinessCity").val(arr[5]);
                  $("#ContentPlaceHolder1_BusinessState").val(arr[6]).prop('selected',true);
                    $("#ContentPlaceHolder1_BusinessZip").val(arr[7]);
                    $("#ContentPlaceHolder1_BusinessWebsite").val(arr[8]);
                   $("#ContentPlaceHolder1_BusinessCategory").val(arr[9]).prop('selected', true);
                    }
                });
            });
        });
    </script>

这是我的 ashx 页面:

   public void ProcessRequest(HttpContext context)
    {
        context.Response.ContentType = "text/html";
        string ID = context.Request.QueryString["ID"];
        SqlConnection conn;
        SqlCommand comm;
        SqlDataReader reader;
        string connectionString = ConfigurationManager.ConnectionStrings["Conn"].ConnectionString;
        conn = new SqlConnection(connectionString);
        comm = new SqlCommand("SELECT BusProfileID, BusinessName, BusinessPhone, BusinessEmail, BusinessAddress, BusinessCity, BusinessState, BusinessZip, BusinessWebsite, BusinessCategory FROM [BusProfile] WHERE BusinessName = @BusinessName", conn);
        comm.Parameters.Add("@BusinessName", System.Data.SqlDbType.VarChar);
        comm.Parameters["@BusinessName"].Value = ID;
        try
        {
            conn.Open();
            reader = comm.ExecuteReader();
            if (reader.Read())
            {
                string BusProfileID = reader["BusProfileID"].ToString();
                string BusinessName = reader["BusinessName"].ToString();
                string BusinessPhone = reader["BusinessPhone"].ToString();
                string BusinessEmail = reader["BusinessEmail"].ToString();
                string BusinessAddress = reader["BusinessAddress"].ToString();
                string BusinessCity = reader["BusinessCity"].ToString();
                string BusinessState = reader["BusinessState"].ToString();
                string BusinessZip = reader["BusinessZip"].ToString();
                string BusinessWebsite = reader["BusinessWebsite"].ToString();
                string BusinessCategory = reader["BusinessCategory"].ToString();

                context.Response.Write(string.Format("{0},{1},{2},{3},{4},{5},{6},{7},{8},{9} ", BusProfileID, BusinessName, BusinessPhone, BusinessEmail, BusinessAddress, BusinessCity, BusinessState, BusinessZip, BusinessWebsite, BusinessCategory));
            }
            reader.Close();
        }

        finally
        {
            conn.Close();
        }
    }

成功后文本框中的数据如下所示:

8,My Business Inc,(702) 555-1212,123@aol.com,555 anywhere street,Los Angeles,California,44502,google.com,Hotel & Travel

Answer 1

这是代码的演示。

var string = "8,my business inc,(702) 555-1212,123@aol.com,555 anywhere street,Los Angeles,california,44502,google.com,hotel and ttravel";

var stringArray = string.split(',');

console.log(stringArray);

结果在这里:

[“8”、“我的公司”、“(702) 555-1212”、“123@aol.com”、“555 Anywhere Street”、“洛杉矶”、“加利福尼亚”、“44502"、"google.com"、"酒店和旅行"]

console.log(xm[5]);

输出: 洛杉矶

如果成功时获得的数据是字符串，那么流程可能如下......

我认为您编写的代码中没有任何错误。

如果数据不是字符串，则

执行 var string = ""+ data; 将其转换为字符串。