php - 如何用sql数据填充chart.js？

Question

我正在使用 Chart.js 在我的页面上生成图表。 不过，我希望这些图表由我的 SQL 数据库填充。 我可以从数据库中获取数据，但不会绘制图表

我的主页上有一个名为“OmzetChart”的 Canvas ，这就是图表应该出现的位置。

<script>
    $.ajax({
        type: 'POST',
        url: 'templates/getdata.php',
        success: function (data) {
            lineChartData = data;
            //alert(JSON.stringify(data));

            var ctx = document.getElementById("OmzetChart").getContext("2d");
            var myLineChart = new Chart(ctx, {
                type: 'line',
                data: lineChartData

            });
       }
    });

</script>

GetData.php 的页面结果如下(这就是我需要的，只是想将其放入我的图表中):

[{"dag":"23","0":"23","uur":"13","1":"13","SomOmzet":"23.00","2":"23.00"},{"dag":"23","0":"23","uur":"18","1":"18","SomOmzet":"2.50","2":"2.50"}]

Getdata.php: 
<?php
include ("../PDO.php");


$conn = DatabasePDO::getInstance();
$sql = "SELECT DATEPART(DD, receiptdatetime) as dag ,DATEPART(hh, receiptdatetime) as uur, ISNULL(abs(cast(sum(NetAmount) as decimal (10,2))),0) as SomOmzet FROM ReceiptLine a , Receipt b, ReceiptLineDetail c 
where a.LineType = 200 and a.receiptID = b.receiptid and a.receiptlineID = c.receiptlineID
group by DATEPART(DD, receiptdatetime), DATEPART(hh, receiptdatetime)";
$st = $conn->prepare($sql);
$st->execute();
$list = array();

while ( $row = $st->fetch() ) {
    $list[] = $row;

}
$conn = null;

echo json_encode( $list );

?>

Answer 1

json_encode()生成一个 JSON 字符串。您需要使用 JSON.parse() 来解析它在您可以使用它之前。

$.ajax({
    type: 'POST',
    url: 'templates/getdata.php',
    success: function (data) {
        lineChartData = JSON.parse(data); //parse the data into JSON

        var ctx = document.getElementById("OmzetChart").getContext("2d");
        var myLineChart = new Chart(ctx, {
            type: 'line',
            data: lineChartData
        });
    }
});

此外，使用 $.ajax()方法的 dataType 参数，您可以将此解析留给 jQuery。

$.ajax({
    type: 'POST',
    url: 'templates/getdata.php',
    dataType: 'json', //tell jQuery to parse received data as JSON before passing it onto successCallback
    success: function (data) {
        var ctx = document.getElementById("OmzetChart").getContext("2d");
        var myLineChart = new Chart(ctx, {
            type: 'line',
            data: data //jQuery will parse this since dataType is set to json
        });
    }
});